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goldfiish [28.3K]
3 years ago
10

Someone please help me I’ll give out brainliest please dont answer if you don’t know

Mathematics
1 answer:
Ede4ka [16]3 years ago
4 0

Answer:

x = 3

Step-by-step explanation:

9x - 5 = 22

Add 5 to both sides

9x = 27

Divide both sides by 9

x = 3

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Find the interval(s) where the function is increasing and the interval(s) where it is decreasing. (Enter your answers using inte
Mashcka [7]

Answer:

f'(x) > 0 on (-\infty ,\frac{1}{e}) and f'(x)<0 on(\frac{1}{e},\infty)

Step-by-step explanation:

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To find its decreasing interval :

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f'(x)=\frac{\mathrm{d} }{\mathrm{d} x}[6-2^{2x}]=\frac{\mathrm{d} }{\mathrm{d}x}[6]-\frac{\mathrm{d}}{\mathrm{d}x}[2^{2x}]=0-[ln(2)*2^{2x}*\frac{\mathrm{d}}{\mathrm{d}x}[2x]=-ln(2)*2^{2x}*2=-ln2*2^{2x+1\Rightarrow }f'(x)=-ln(2)*2^{2x}*2\\-ln(2)*2^{2x+1}=-2x^{2x}(ln(x)+1)=0

2.2 Solving for x this equation, this will lead us to one critical point since x'  is not defined for Real set, and x''=\frac{1}{e}≈0.37 for e≈2.72

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3) Finally, check it out the critical point, i.e. f'(x) >0 and below f'(x)<0.

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To make the new graph, translate every point down 5 units.

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