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goldfiish [28.3K]
3 years ago
10

Someone please help me I’ll give out brainliest please dont answer if you don’t know

Mathematics
1 answer:
Ede4ka [16]3 years ago
4 0

Answer:

x = 3

Step-by-step explanation:

9x - 5 = 22

Add 5 to both sides

9x = 27

Divide both sides by 9

x = 3

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Once simplified, which of the expressions below is equal to 14x+3? Select all that apply.
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Answer:

A and B

Step-by-step explanation:

9x+9+5x-6

14x+3

32x+8-18x-5

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Find the value of x..
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Step-by-step explanation:

Because this shape is a quadrilateral, so the sum of the angles of a quadrilateral is a total of 360 degrees. So i added 90 + 90 + 64 = 244. And 360 - 244 = 116.

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ladder is 8 ft long . The ladder needs to reach to a window that is 6 ft above the ground . How far away from the house should t
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47 square units is the answer on edge
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3 years ago
Situation:
Gala2k [10]

Answer:

5.5 days (nearest tenth)

Step-by-step explanation:

<u>Given formula:</u>

\sf N=N_0e^{-kt}

  • \sf N_0 = initial mass (at time t=0)
  • N = mass (at time t)
  • k = a positive constant
  • t = time (in days)

Given values:

  • \sf N_0 = 11 g
  • k = 0.125

Half-life:  The <u>time</u> required for a quantity to reduce to <u>half of its initial value</u>.

To find the time it takes (in days) for the substance to reduce to half of its initial value, substitute the given values into the formula and set N to half of the initial mass, then solve for t:

\begin{aligned}\sf N & = \sf N_0e^{-kt}\\\\\implies \sf \dfrac{11}{2} & = \sf 11e^{-0.125t}\\\\\sf \dfrac{1}{2} & = \sf e^{-0.125t}\\\\\sf \ln \left(\dfrac{1}{2}\right) & = \sf \ln e^{-0.125t\\\\\sf \ln \left(\dfrac{1}{2}\right) & = \sf -0.125t \ln e\\\\\sf \ln \left(\dfrac{1}{2}\right) & = \sf -0.125t(1)\\\sf t & = \sf \dfrac{\ln \left(\dfrac{1}{2}\right)}{-0.125}\\\\\sf t & = \sf 5.545177444...\\\\\sf t & = \sf 5.5\:\:days\:\:(nearest\:tenth)\end{aligned}

Therefore, the substance's half-life is 5.5 days (nearest tenth).

Learn more about solving exponential equations here:

brainly.com/question/28016999

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