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3 years ago

list down some examples of solutions that we need to prepare/make in the form of unsaturated and saturated solution

Chemistry

1 answer:

Vladimir79 [104]3 years ago

5 0

Answer:

1)Carbonated water is saturated with carbon, hence it gives off carbon through bubbles.

2)Adding sugar to water until it no longer dissolves creates a saturated solution.

3)Continuing to dissolve salt in water until it will no longer dissolve creates a saturated solution.

An unsaturated tea and sugar solution would be one into which you could add more sugar and have the sugar still dissolve

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Answer:

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3 years ago

12. Convert 600 mg to grams. Show your work.

nadya68 [22]

Answer:

600 milligrams=0.6 grams

Explanation:

1 milligram=0.001 grams and 1 gram= 1000 milligrams

So, to convert milligrams to grams, multiply the mg value by 0.001 or divide by 1,000.

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If you want to know how many grams 300 mg is, you would divide 300 by 1,000, which would get you 0.3 grams.

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3 years ago

Percent composition?: 85.05 g of Mg combines completely with 112.21 g of S.

bogdanovich [222]

Empirical Formula = C20 H60 HG1 S1 O4 (numbers should be in subscript)

Percent Composition =

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4 years ago

A chemist must prepare 300.0mL of nitric acid solution with a pH of 0.70 at 25°C. He will do this in three steps: Fill a 300.0mL

d1i1m1o1n [39]

<u>Answer:</u> The volume of concentrated solution required is 9.95 mL

<u>Explanation:</u>

To calculate the pH of the solution, we use the equation:

$pH=-\log[H^+]$

We are given:

pH = 0.70

Putting values in above equation, we get:

$0.70=-\log[H^+]$

$[H^+]=10^{-0.70}=0.199M$

1 mole of nitric acid produces 1 mole of hydrogen ions and 1 mole of nitrate ions.

Molarity of nitric acid = 0.199 M

To calculate the volume of the concentrated solution, we use the equation:

$M_1V_1=M_2V_2$

where,

$M_1\text{ and }V_1$ are the molarity and volume of the concentrated nitric acid solution

$M_2\text{ and }V_2$ are the molarity and volume of diluted nitric acid solution

We are given:

$M_1=7.0M\\V_1=?mL\\M_2=0.199M\\V_2=350mL$

Putting values in above equation, we get:

$7.0\times V_1=0.199\times 350.0\\\\V_1=\frac{0.199\times 350}{7.0}=9.95mL$

Hence, the volume of concentrated solution required is 9.95 mL

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3 years ago

list down some examples of solutions that we need to prepare/make in the form of unsaturated and saturated solution​

list down some examples of solutions that we need to prepare/make in the form of unsaturated and saturated solution