The volume of soup in the cylindrical can is 100.48 inches cube.
<h3>How to find the volume of a cylindrical can?</h3>
We have to find the volume of the soup in a cylindrical can of height 8 inches and 4 inches across the lid.
The volume of the soup is the volume of the cylindrical can.
Therefore,
volume of the cylindrical can = πr²h
where
- r = radius of the cylinder
- h = height of the cylinder
Therefore,
h = 8 inches
r = 4 / 2 = 2 inches
volume of the soup in the cylindrical can = πr²h
volume of the soup in the cylindrical can = π × 2² × 8
volume of the soup in the cylindrical can = π × 4 × 8
volume of the soup in the cylindrical can = 32π
Therefore,
volume of the soup in the cylindrical can = 32 × 3.14
volume of the soup in the cylindrical can = 100.48 inches³
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750/1000
Divide both numbers by 50. You get 15/20
Answer:
first number is negative 2, second is 1
Step-by-step explanation:
-2×4= -8 1×9=9
-8+9=1
-2×4= -8 1×6=6
-8+6= -2
hope this helped
Answer:
3x-4x7
Step-by-step explanation:
Answer:
Answers:
Rate of change = -5
Initial value = 25
Step-by-step explanation:
Each time x increases by 2 (eg from x = 1 to x = 3), the value of y drops by 10 (eg from y = 20 to y = 10)
Therefore the slope is...
slope = rise/run = (change in y)/(change in x) = -10/2 = -5
slope = -5
So each time x increases by 1, y will decrease by 5
Flip things around: each time x decreases by 1, y will increase by 5
So the pair (x,y) = (1,20) shown in row 1 of the table leads to (0,25) based on the rule above. Another way to see this is to plug m = -5, x = 1 and y = 20 into y = mx+b and solve for b to get b = 25