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Margarita [4]
2 years ago
9

Im Not completely sure what this is asking, but can someone please help answer this

Mathematics
1 answer:
solmaris [256]2 years ago
7 0

Answer:

the answer is 60

Step-by-step explanation:

because 2(30)=60

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25-3x-2-4x+5 has how many coefficients and how many expressions
adoni [48]

Answer:

This expression has 2 coefficients, (-3 and -4), because any number with a variable is a coefficient. That means 25, -2, and 5 are all constants, because they don't have variables.

Variables are the x's in this case.

I hope this answers your question :) Also if you like, can you mark me brainliest, please? It would really mean a lot to me :)

3 0
2 years ago
HELP ASAP PLEASE!!
Mama L [17]

Answer:

Step-by-step explanation:

According to the table, function g(x) reaches the max height of 33, approx.

The equation of motion is f(x) = -16x^2 + 42x + 12.  We need to determine the maximum of this function.  To do this, find the x-coordinate of the vertex, which is x = -b/(2a), or x = -42/(2*-16), or 1.31 sec.

Evaluating f(x) = -16x^2 + 42x + 12 at x = 1.31 sec, we get f(1.31) = 39.6.

So it appears that f(x) has a higher max than does g(x); the difference is approx. 39.6 - 33, or 6.6

6 0
3 years ago
Adam proposes that his mother changes his allowance according to the
olga2289 [7]

Answer:

a.) $3.20

b.) $102.40

$3,276.80

Step-by-step explanation:

0.2 times 2 five times is 3.2

0.2 times 2 ten times is 102.4

0.2 times 2 fifteen times is 3,276.8

7 0
3 years ago
AYUDA CON ESTO!!! ALGUIEN PORFAVOR
Gre4nikov [31]

Answer:

Problem 1)  frequency:  160 heartbeats per minute, period= 0.00625 minutes (or 0.375 seconds)

Problem 2) Runner B has the smallest period

Problem 3) The sound propagates faster via a solid than via air, then the sound of the train will arrive faster via the rails.

Step-by-step explanation:

The frequency of the football player is 160 heartbeats per minute.

The period is (using the equation you showed above):

Period = \frac{1}{frequency} = \frac{1}{160} \,minutes= 0.00625\,\,minutes = 0.375\,\,seconds

second problem:

Runner A does 200 loops in 60 minutes so his frequency is:

\frac{200}{60} = \frac{10}{3} \approx  3.33   loops per minute

then the period is: 0.3 minutes (does one loop in 0.3 minutes)

the other runner does 200 loops in 65 minutes, so his frequency is:

\frac{200}{65} = \frac{40}{13} \approx  3.08   loops per minute

then the period is:

\frac{13}{40} =0.325\,\,\,minutes

Therefore runner B has the smaller period

8 0
3 years ago
There are 80 sixth graders at Wilson Middle School. Only 70% of the sixth graders will attend the morning assembly. How many six
zysi [14]
1 student will attend the assembly in the morning
4 0
3 years ago
Read 2 more answers
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