Im Not completely sure what this is asking, but can someone please help answer this
1 answer:
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Answer:
As follows,
Step-by-step explanation:
Find the attachment.
Distance of PQ=√13
Distance of QR=√13
Distance of PR=√26
Thus, PQR is an isosceles triangle.
Distance of MN=√(16+(a-2)^2)
16=16+a^2-4a+4
a^2-4a+4=0
a=2
Distance of RS=√(9+(b+1)^2)
25=9+b^2+2b+1
b=3 or -5
Distance of RS=√(9+(-1-c)^2)
18=9+c^2 + 2 c + 1
c=-4,2
