Help me plz Write a phrase as an algebraic expression when n = the number. (a number minus 4)

Mrs. Datz had to make a visit to the bank because her account was overdrawn

Alexeev081 [22]

Answer:

The answer of this question is $68.

3 0

3 years ago

Read 2 more answers

Health insurance benefits vary by the size of the company (the Henry J. Kaiser Family Foundation website, June 23, 2016). The sa

xxMikexx [17]

Answer:

$\chi^2 = \frac{(32-42)^2}{42}+\frac{(18-8)^2}{8}+\frac{(68-63)^2}{63}+\frac{(7-12)^2}{12}+\frac{(89-84)^2}{84}+\frac{(11-16)^2}{16}=19.221$

Now we can calculate the degrees of freedom for the statistic given by:

$df=(rows-1)(cols-1)=(3-1)(2-1)=2$

And we can calculate the p value given by:

$p_v = P(\chi^2_{2} >19.221)=0.000067$

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(19.221,2,TRUE)"

Since the p values is higher than a significance level for example $\alpha=0.05$ , we can reject the null hypothesis at 5% of significance, and we can conclude that the two variables are dependent at 5% of significance.

Step-by-step explanation:

Previous concepts

A chi-square goodness of fit test "determines if a sample data matches a population".

A chi-square test for independence "compares two variables in a contingency table to see if they are related. In a more general sense, it tests to see whether distributions of categorical variables differ from each another".

Solution to the problem

Assume the following dataset:

Size Company/ Heal. Ins. Yes No Total

Small 32 18 50

Medium 68 7 75

Large 89 11 100

_____________________________________

Total 189 36 225

We need to conduct a chi square test in order to check the following hypothesis:

H0: independence between heath insurance coverage and size of the company

H1: NO independence between heath insurance coverage and size of the company

The statistic to check the hypothesis is given by:

$\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}$

The table given represent the observed values, we just need to calculate the expected values with the following formula $E_i = \frac{total col * total row}{grand total}$

And the calculations are given by:

$E_{1} =\frac{50*189}{225}=42$

$E_{2} =\frac{50*36}{225}=8$

$E_{3} =\frac{75*189}{225}=63$

$E_{4} =\frac{75*36}{225}=12$

$E_{5} =\frac{100*189}{225}=84$

$E_{6} =\frac{100*36}{225}=16$

And the expected values are given by:

Size Company/ Heal. Ins. Yes No Total

Small 42 8 50

Medium 63 12 75

Large 84 16 100

_____________________________________

Total 189 36 225

And now we can calculate the statistic:

$\chi^2 = \frac{(32-42)^2}{42}+\frac{(18-8)^2}{8}+\frac{(68-63)^2}{63}+\frac{(7-12)^2}{12}+\frac{(89-84)^2}{84}+\frac{(11-16)^2}{16}=19.221$

Now we can calculate the degrees of freedom for the statistic given by:

$df=(rows-1)(cols-1)=(3-1)(2-1)=2$

And we can calculate the p value given by:

$p_v = P(\chi^2_{2} >19.221)=0.000067$

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(19.221,2,TRUE)"

Since the p values is higher than a significance level for example $\alpha=0.05$ , we can reject the null hypothesis at 5% of significance, and we can conclude that the two variables are dependent at 5% of significance.

3 0

3 years ago

Consider the Polynomial P(x)=x^3-5x^2-x+5. is (x-5) a factor?

Alborosie

Answer:

Option B, Yes, the remainder is 0, so x-5 is a factor of P(x)

Step-by-step explanation:

Step 1: Factor

p(x) = x^3 - 5x^2 - x + 5

p(x) = (x - 5)(x + 1)(x - 1)

Yes, the remainder is 0 so, x-5 is a factor of p(x)

Answer: Option B, Yes, the remainder is 0, so x-5 is a factor of P(x)

8 0

3 years ago

Please answer the question

Lady bird [3.3K]

Answer:

the first one is

+2 +4 + 8 + 16 +32

he multiply by 2 every time he add numbers so its 65

the second one he make this

-8 -4 -2 -1

every time he Take from numbers he devide by 2

so its 5

the third one

+6 +18 + 54 + 162

every time he add he multiply by 3

ao its 162 +80 =242

the fourth one is

+33 +66 + 132 +264

he multiply by 2 every time he add

so its 267+264=531

the fiveth one is

he put the roots

2²,3²,4²,5²,6²

so the answer is 36

Step-by-step explanation:

A 65

B 5

C 242

D 531

E 36

hopefully its helpful man

6 0

3 years ago

F(x)=x^3 −9x What is the average rate of change of over the interval [1,6]?

Inga [223]

Answer:

34

Step-by-step explanation:

The average rate of change of f(x) in the closed interval [ a, b ] is

$\frac{f(b)-f(a)}{b-a}$

Here [ a, b ] = [ 1, 6 ], thus

f(b) = f(6) = 6³ - 9(6) = 216 - 54 = 162

f(a) = f(1) = 1³ - 9(1) = 1 - 9 = - 8

average rate of change = $\frac{162-(-8)}{6-1}$ = $\frac{170}{5}$ = 34

8 0

3 years ago