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3 years ago

What is the net force acting upon this object? *

Physics

2 answers:

zalisa [80]3 years ago

5 0

Answer:

2 N Right

Explanation:

Net force = 5 - 3

= 2 N to the Right

AnnZ [28]3 years ago

4 0

2 N Right

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Newton's second law of motion states the relationship of mass, acceleration and force. It states that

sergey [27]

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3 years ago

(a) Calculate the magnitude of the angular momentum of the earth in a circular orbit around the sun. Is it reasonable to model i

Anni [7]

Answer:

(a) $L=2.6742\times 10^{40}\, kg.m^2.s^{-1}$

(b) $L_s=7.07 \times 10^{23} \, kg.m^2.s^{-1}$

Explanation:

<u>For Earth we have:</u>

mass of earth, $m_E=5.97\times 10^{24}\, kg$

radius of earth, $R_E=6.38\times 10^6m$

orbital radius, $r=1.5 \times 10^{11}m$

period of rotation, $t_{rot}=24h=86400\, s$

period of revolution, $t_{rev}= 1 yr=3.156\times 10^7 s$

(a)

Angular momentum, $L=?$

∵ $L=I.\omega$ ...............................(1)

For a particle of mass m moving in a circular path at a distance r from the axis,

$I=m.r^2$

& $v=r.\omega$

Putting respecstive values in eq. (1)

$L=m_E\times r^{2}\times \omega$

$L=5.97\times 10^{24}\times (1.5 \times 10^{11})^2\times \frac{2\pi}{3.156\times 10^7}$

$L=2.6742\times 10^{40}\, kg.m^2.s^{-1}$

To model earth as a particle is reasonable because the distance between the sun and the earth is very large s compared to the radius if the earth.

(b)

For a uniform sphere of mass M and radius R and an axis through its center, $I=\frac{2}{5}M.R^2$

using eq. (1)

$L_s=(\frac{2}{5}m_E.R_E^2) \omega$

$L_s=\frac{2}{5} \times 5.97\times 10^{24} \times 6.38\times 10^6\times \frac{2\pi}{86400}$

$L_s=7.07 \times 10^{23} \, kg.m^2.s^{-1}$

6 0

3 years ago

Define Laws of motion

Dmitriy789 [7]

Answer:

Explanation:

NEWTON'S FIRST LAW OF MOTION:

a body continues its state of rest or of uniform motion in a straight line provided no net force acts on it. Fnet=0

NEWTON'S SECOND LAW OF MOTION:

when a net force acts on a body it produces acceleration in the body which is directly proportional to the magnitude of the net force and inversely to the mass of the body.F=ma

NEWTON'S THIRD LAW OF MOTION:

to every action there is always an equal but opposite reaction.

8 0

3 years ago

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