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3 years ago

A large truck and a small car have a head-on collision. Which scenario is true?

Physics

2 answers:

solmaris [256]3 years ago

7 0

B. is the answer dude

g100num [7]3 years ago

6 0

Answer:

The correct answer is option C. By Newton's third law. The force that the car exerts on the truck is equal in magnitude but opposite in direction to the force the truck exerts on the car.

Explanation:

From Newton's third law which states that action and reaction are equal but opposite in direction. The forces between both vehicles are the same in magnitude but opposite in direction. Although they apply forces of equal magnitude on each other, the effect of this force is different on each of the vehicles.

From Newton's second law this force is related to the acceleration of each vehicle by the formula

F = mass × acceleration

If this force is the same in magnitude for both vehicles and let the mass of the truck and car be M and m respectively.

Let a(truck) and a(car) represent the accelerations of the truck and car respectively.

Then,

F = M×a(truck) = m×a(car)

Obviously the truck is a bigger vehicle than the car so, M > m. Since M > m the acceleration of the truck will be lesser than the acceleration of the car. This is a very practical result that happens almost everyday. The car on colliding with the truck bouces back at high speed while the truck on the other hand moves only a little distance because of its mass.

So, basically for the same magnitude of force, the greater the mass the lesser the acceleration and vice versa. Thank you for reading.

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Vlad1618 [11]

Answer:

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Explanation:

3 0

3 years ago

Read 2 more answers

The electrical force on a 2-c charge is 60 n. the electric field where the charge is located is

Kazeer [188]

The electrical force acting on a charge q immersed in an electric field is equal to
$F=qE$
where
q is the charge
E is the strength of the electric field

In our problem, the charge is q=2 C, and the force experienced by it is
F=60 N
so we can re-arrange the previous formula to find the intensity of the electric field at the point where the charge is located:
$E= \frac{F}{q}= \frac{60 N}{2 C}=30 N/C$

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3 years ago

Assume that the polymer material has a constant refractive index of 1.5. For light of 600nm wavelength at normal incidence, what

yaroslaw [1]

Answer:

Minimum thickness will be 100 nm

Explanation:

We have given refractive index is n = 1.5

Wavelength of the light incidence $\lambda$ = 600 nm

We have to find the smallest thickness of the film so that there will be minimum light reflect

For minimum thickness of non reflecting film

$t=\frac{\lambda }{4n}$ , here t is thickness, $\lambda$ is wavelength and n is refractive index

Putting all values $t=\frac{600}{4\times 1.5}=100nm$

So minimum thickness will be 100 nm

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3 years ago

An student in a swimming pool weighs 450 N and in a regular balance out of the swimming pool weighs 700 N. What is the value of

rewona [7]

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3 years ago

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frosja888 [35]

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3 years ago