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vitfil [10]
2 years ago
12

Can some help with this? id appreciate your help :)

Physics
1 answer:
Slav-nsk [51]2 years ago
6 0

Answer:

I am not really sure but i think its option 2

Explanation:

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Calculate the displacement of a motorcycle that accelerates forward from rest to 7.0 m/s in 3.5 s.
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Answer:

12.25 meters

Explanation:

s=1/2(v+u)t

s= displacement

v= final velocity

u= initial velocity

t= time

7m/s+0m/s divide by 2= 3.5 m/s velocity  Times 3.5 seconds=  12.25 meters

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I believe D is the correct answer
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2 years ago
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You have landed on an unknown planet, Newtonia, and want to know what objects will weigh there. You find that when a certain too
steposvetlana [31]

Answer:

w'=5.679\ N on the planet

w=22.43\ N on earth

Explanation:

Given:

  • initial velocity of the tool before pushing, u=0\ m.s^{-1}
  • force applied on the tool, F=12\ N
  • displacement of the tool, s=16.4\ m
  • time taken for the displacement, t=2.5\ s
  • height of releasing  the tool, h=10.3\ m
  • time taken by the tool to fall on the ground, t_v=2.88\ s

<u>Now using the equation of motion:</u>

s=u.t+\frac{1}{2}a.t^2

where:

a = acceleration of the object

16.4=0+0.5\times a\times 2.5^2

a=5.248\ m.s^{-2}

Now the mass of the tool:

m=\frac{F}{a}

m=\frac{12}{5.248}

m=2.2866\ kg

<u>Using the equation of motion when the tool is dropped:</u>

h=u.t_v+\frac{1}{2} \times g.t_v^2

here:

g = acceleration due to gravity on the planet

10.3=0+0.5\times a\times 2.88^2

g=2.4836\ m.s^{-2}

Weight of the tool in the planet:

w'=m.g

w'=2.2866\times 2.4836

w'=5.679\ N

Weight of the tool on the earth:

w=m.g'

w=2.2866\times 9.81

w=22.43\ N

8 0
3 years ago
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Elements in group 1 are known as ___________ metals. Alkaline Transition Alkali Inner Transition
ss7ja [257]
Alkali

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Hope this is the brainliest answer.
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