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Helen [10]
3 years ago
7

Answer please!!  I really need help with thissssssssss! :(

Mathematics
1 answer:
andriy [413]3 years ago
6 0

Answer:

It's the Best answer B

Step-by-step explanation:

Because yes is línea test

You no understand put the B answer friend

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What number ten more than 985
Ksenya-84 [330]

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6 0
4 years ago
HELP ASAP <br> IF YOU TAKE THE POINTS IM REPORTING U<br> QUESTION IN PIC
Andrew [12]
Let's call the number x. So four times the number minus five would look like
4x-5
Twice the number plus three would look like
2x+3
Now make the two equations equal
4x-5=2x+3
I'm going to subtract 2x from each side
2x-5=3
Now I'm going to add five to each side
2x=8
Now divide both sides by 2
x=4
To double check, just plug back into the original equations
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7 0
3 years ago
Read 2 more answers
What integer multiplied by 8 equals -96?
Gwar [14]

Answer:

-12

Step-by-step explanation:

Let "integer" = x

When x is multiplied by 8, it equals -96:

8x = -96

Isolate the variable x. Note the equal sign, what you do to one side, you do to the other. Divide 8 from both sides

(8x)/8 = (-96)/8

x = -96/8

x = -12

-12 is your answer

~

3 0
3 years ago
Suppose we have 14 boxes of pastries (each box of a different flavor), each with a scone and a muffin inside. For example, one b
Nat2105 [25]

Answer:

Step-by-step explanation:

5 0
3 years ago
A random sample from a normal population is obtained, and the data are given below. Find a 90% confidence interval for . 114 157
melamori03 [73]

Answer:

103.160 \leq \sigma \leq 187.476

And the upper bound rounded to the nearest integer would be 187.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population mean or variance lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.

The Chi Square distribution is the distribution of the sum of squared standard normal deviates .

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

Solution to the problem

Data given: 114 157 203 257 284 299 305 344 378 410 421 450 478 480 512 533 545

The confidence interval for the population variance \sigma^2 is given by the following formula:

\frac{(n-1)s^2}{\chi^2_{\alpha/2}} \leq \sigma \leq \frac{(n-1)s^2}{\chi^2_{1-\alpha/2}}

On this case we need to find the sample standard deviation with the following formula:

s=sqrt{\frac{\sum_{i=1}^{17} (x_i -\bar x)^2}{n-1}}

And in order to find the sample mean we just need to use this formula:

\bar x =\frac{\sum_{i=1}^n x_i}{n}

The sample mean obtained on this case is \bar x= 362.941 and the deviation s=132.250

The next step would be calculate the critical values. First we need to calculate the degrees of freedom given by:

df=n-1=17-1=16

Since the Confidence is 0.90 or 90%, the value of \alpha=0.1 and \alpha/2 =0.05, and we can use excel, a calculator or a tabel to find the critical values.  

The excel commands would be: "=CHISQ.INV(0.05,16)" "=CHISQ.INV(0.95,16)". so for this case the critical values are:

\chi^2_{\alpha/2}=26.296

\chi^2_{1- \alpha/2}=7.962

And replacing into the formula for the interval we got:

\frac{(16)(132.250)^2}{26.296} \leq \sigma \leq \frac{(16)(132.250)^2}{7.962}

10641.959 \leq \sigma^2 \leq 35147.074

Now we just take square root on both sides of the interval and we got:

103.160 \leq \sigma \leq 187.476

And the upper bound rounded to the nearest integer would be 187.

4 0
4 years ago
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