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Elza [17]
3 years ago
14

The area of a parallelogram is 513cm² and the height is 19cm. Calculate the base length.

Mathematics
1 answer:
lidiya [134]3 years ago
8 0
The base length is 27 cm.
area of a parallelogram is A=b*h
plug in the known area and height into the formula: 513=19*b
divide off the 19: b=27
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Which number is a perfect cube? 5, 100, 125, 150​
KATRIN_1 [288]

Answer:

125

Step-by-step explanation:

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3 years ago
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Given: sinθ = -3/5, θ is a third quadrant angle, and tan φ = -7/24, φ is a second-quadrant angle; find cos(θ + φ])
Natali [406]

Answer:

First option: cos(θ + φ) = -117/125

Step-by-step explanation:

Recall that cos(θ + φ) = cos(θ)cos(φ) - sin(θ)sin(φ)

If sin(θ) = -3/5 in Quadrant III, then cos(θ) = -4/5.

Since tan(φ) = sin(φ)/cos(φ), then sin(φ) = -7/25 and cos(φ) = 24/25 in Quadrant II.

Therefore:

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cos(θ + φ) = (-4/5)(24/25) - (-3/5)(-7/25)

cos(θ + φ) = (-96/125) - (21/125)

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8 0
2 years ago
A sample of 38 observations is selected from one population with a population standard deviation of 3.4. The sample mean is 100.
kaheart [24]

Answer:

a. two-tailed test

b. reject H0 if Z>1.96 or Z<-1.96

c. Z = 1.73

d. we have failed to reject the null hypothesis

e. P-value = 0.0418

Step-by-step explanation:

We will use a Z test to resolve this, an it will be a two-tailed test because the hypothesis statements are not indicating a specific direction for the significant difference (H0 : μ1 = μ2 ; H1 : μ1 ≠ μ2), this also means that the significanclevel will be divided between the both tails (2.5% en each tail for the rejection regions). See attached drawing for reference.

We need to find our critical value:

Zα/2 = Z(0.05/2) = 0.025

If we look for 0.025 in a Z table we will find that the critical value is 1.96 to the right, and by symmetry -1.96 to the left. So our decision rule will be to reject H0 if Z>1.96 or Z<-1.96

The Z test will be done using the next equation:

Z = (x⁻1 - x⁻2) - (μ1 - μ2) / √( σ²1/n1 + σ²2/n2

Because we are testing the null hypothesis we know that μ1 - μ2 must be zero if they are supposed to be equal (H0 : μ1 = μ2), so we calculate as follows:

Z = (100.5 - 98.8) - (0) / √( (3.4)²/38 + (5.8)²/51 = 1.7/0.9817 = 1.73

Z<1.96, therefore we have failed to reject the null hypothesis

The P-value for this test would be represented by the probability of Z being greater than 1.73, so we can look for it in any Z table, finding that its value is 0.0418, and because P-value>0.025 we again confirm that we don't have evidence statistically significant to reject the null hypothesis

4 0
3 years ago
Calculate the frequency of a wave with a speed of 250m/s and a wavelength of 50m.
WARRIOR [948]

Answer:

<h3>formulas</h3>

<em><u>frequency</u></em><em><u>=</u></em><em><u>spee</u></em><em><u>d</u></em><em><u>/</u></em><em><u>wavele</u></em><em><u>ngth</u></em>

<em><u>f</u></em><em><u>=</u></em><em><u>2</u></em><em><u>5</u></em><em><u>0</u></em><em><u>/</u></em><em><u>5</u></em><em><u>0</u></em>

<em><u>f</u></em><em><u>=</u></em><em><u>5</u></em><em><u>0</u></em><em><u>h</u></em><em><u>z</u></em>

7 0
2 years ago
Hiran invests 20 000 rupees in an account for 3 years at 1.5% per year compound interest.
svp [43]

Answer:

There will be 20 914 rupees in the amount at the end of 3 years.

Step-by-step explanation:

The amount of rupes after t years in compound interest is given by:

A(t) = A(0)(1+r)^{t}

In which A(0) is the initial amount and r is the interest rate, as a decimal.

Hiran invests 20 000 rupees in an account for 3 years at 1.5% per year compound interest.

This means that A(0) = 20000, r = 0.015. So

A(t) = A(0)(1+r)^{t}

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A(t) = 20000(1.015)^{t}

Work out the total amount of money in the account at the end of 3 years.

This is A(3). So

A(3) = 20000(1.015)^{3} = 20913.6

Rounding to the nearest rupee.

There will be 20 914 rupees in the amount at the end of 3 years.

8 0
2 years ago
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