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IgorC [24]
3 years ago
8

A rectangular shape parking lot is to have a perimeter of 550 yards. If the width must be 93 yards because of a building code wh

at was the length need to be
Mathematics
1 answer:
svetlana [45]3 years ago
8 0

Answer:

the length= 182 yards

Step-by-step explanation:

perimeter =550

width =93

length =x

perimeter of a rectangle = 2 length (2l)+ 2 width (2w)

550=2l+ 2(93)

550=2l+186

550-186=2l

364=2l

364/2 = 2l/2

182=l

therefore length(l) =182yards

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2 years ago
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Vikentia [17]
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3 years ago
I will give brainliest
Alja [10]

1. The answer is 16^2, so B.

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3 0
3 years ago
Evaluate the following integral using trigonometric substitution
serg [7]

Answer:

The result of the integral is:

\arcsin{(\frac{x}{3})} + C

Step-by-step explanation:

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\int \frac{dx}{\sqrt{9-x^2}}

Trigonometric substitution:

We have the term in the following format: a^2 - x^2, in which a = 3.

In this case, the substitution is given by:

x = a\sin{\theta}

So

dx = a\cos{\theta}d\theta

In this question:

a = 3

x = 3\sin{\theta}

dx = 3\cos{\theta}d\theta

So

\int \frac{3\cos{\theta}d\theta}{\sqrt{9-(3\sin{\theta})^2}} = \int \frac{3\cos{\theta}d\theta}{\sqrt{9 - 9\sin^{2}{\theta}}} = \int \frac{3\cos{\theta}d\theta}{\sqrt{9(1 - \sin^{\theta})}}

We have the following trigonometric identity:

\sin^{2}{\theta} + \cos^{2}{\theta} = 1

So

1 - \sin^{2}{\theta} = \cos^{2}{\theta}

Replacing into the integral:

\int \frac{3\cos{\theta}d\theta}{\sqrt{9(1 - \sin^{2}{\theta})}} = \int{\frac{3\cos{\theta}d\theta}{\sqrt{9\cos^{2}{\theta}}} = \int \frac{3\cos{\theta}d\theta}{3\cos{\theta}} = \int d\theta = \theta + C

Coming back to x:

We have that:

x = 3\sin{\theta}

So

\sin{\theta} = \frac{x}{3}

Applying the arcsine(inverse sine) function to both sides, we get that:

\theta = \arcsin{(\frac{x}{3})}

The result of the integral is:

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8 0
3 years ago
Write an equation in point-slope form for the line that satisfies the given set of conditions.
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4 0
2 years ago
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