Answer:
No solution
Step-by-step explanation:
-3x + 3y = 4
-x + y = 3
<u>Solve the equation for x:</u>
<u>Move the variable to the right side and change its sign</u>
-x + y = 3
-x = 3 - y
<u>Change the signs on both sides of the equation</u>
-x = 3 - y
x = -3 + y
<u>Substitute the given value of x into the equation -3x + 3y = 4</u>
-3x + 3y = 4
x = -3 + y
-3(-3+y)+3y=4
<u>Solve the equation for y</u>
-3(-3+y)+3y=4
y = 0
There is no solution for y.
And since there's no solution for y, the system has no solution.
Answer:
r = 8
Step-by-step explanation:
V = π r^2 h so 383 = r^2 (6)
383 / 6 = r^2
64 = r^2 so
r = 8
Hello from MrBillDoesMath!
Answer:
See Discussion section below
Discussion:
2x^2 + 5x + 3 = (2x+3)(x+1) which is Choice 3
3x^2+10x+4 =-1/3 (-3 x + sqrt(13) - 5) (3 x + sqrt(13) + 5)
I don't think any of the provided choices are right!
8x^2+10x-3 = (2x+3)(4x-1) which is Choice 2
6x^2-7x-4 = -1/24 (-12 x + sqrt(145) + 7) (12 x + sqrt(145) - 7)
I don't think any of the provided choices are right!
2x^2+x-28 = (2x-7)(x+4) which is Choice 2
Thank you,
MrB
Answer:
(4,12)
(-1,-3)
Step-by-step explanation:
x^2 - y = 4
y = 3x
Use substitution. Substitute 3x for y in the first equation
x^2 - (3x) = 4
x^2 -3x =4
Subtract 4 from each side
x^2 -3x -4 = 4-4
x^2 -3x-4 =0
Factor
(x-4) (x+1) =0
Using the zero product property
x-4 =0 x+1 =0
x=4 x=-1
Now to find y for each x solution
x=4
y =3x = 3(4) =12
(4,12)
x=-1
y =3x = 3(-1) =-3
(-1,-3)
A&C
B&F
Try it by fold the prism with paper
