Answer:
H0 : μ ≤ x
H1 : μ > x
The hypothesis :
The null hypothesis, H0 : μ ≤ x
The alternative hypothesis, uses the Friday score samples to compare the hypothesis ;
The alternative hypothesis, H1 : μ > 8
For then null, the mean scores is assumed to be the same, and has such mean of Friday's test score takes the value of the population.
Let the population mean value = x
The alternative hypothesis is the claim that the sampled mean gives a greater value than the population mean :
H1 : μ > x
In this relation we have two ordered pairs:
( 5, 7 ) and ( 5, 8 )
For x = 5 : f ( x ) = 7 and also for x = 5, f ( x ) = 8. This is not possible for a function.
Answer:
b ) No. The relation is not a function.
If points f and g are symmetric with respect to the line y=x, then the line connecting f and g is perpendicular to y=x, and f and g are equidistant from y=x.
This problem could be solved graphically by graphing y=x and (8,-1). With a ruler, measure the perpendicular distance from y=x of (8,-1), and then plot point g that distance from y=x in the opposite direction. Read the coordinates of point g from the graph.
Alternatively, calculate the distance from y=x of (8,-1). As before, this distance is perpendicular to y=x and is measured along the line y= -x + b, where b is the vertical intercept of this line. What is b? y = -x + b must be satisfied by (8,-1): -1 = -8 + b, or b = 7. Then the line thru (8,-1) perpendicular to y=x is y = -x + 7. Where does this line intersect y = x?
y = x = y = -x + 7, or 2x = 7, or x = 3.5. Since y=x, the point of intersection of y=x and y= -x + 7 is (3.5, 3.5).
Use the distance formula to determine the distance between (3.5, 3.5) and (8, -1). This produces the answer to this question.
The answer would be 12/54 (twelve fifty fourths) but if you simplify it you would get 2/9 (two ninths).