Solve for y (4y+7) (3y+5)

Mathematics

2 answers:

Artist 52 [7]3 years ago

5 0

Answer:

Step-by-step explanation:

(4y + 7) + (3y + 5) = 180. (angle on a straight line =180)

4y + 7 + 3y + 5 =180

4y + 3y + 7 + 5 = 180

7y + 12 = 180

7y = 180 - 12

7y = 168

y = 168/7

y = 24

Ymorist [56]3 years ago

3 0

Answer:

24 if im correct

Step-by-step explanation:

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A 14-foot ladder is leaning against a building as shown. It touches a point 11 feet up on a building. How far away from the base

Luden [163]

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A^2 + B^2 = C^2

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6 0

3 years ago

Let A = { x ∈ R : x 2 − 5 x + 4 ≤ 0 } , B = (3 , 5), and C = (3 , 4]. Show that A ∩ B = C . (Recall, you must show two separate

kolbaska11 [484]

Answer:

You can proceed as follows:

Step-by-step explanation:

First solve the quadratic inequality $x^{2}-5x+4\leq 0$ . To do that, factorize, then we have that $(x-4)(x-1)\leq 0$ . This implies that

$x-1\leq 0\, \text{and}\, x-4\geq 0$

$x-1 \geq 0\, \text{and}\, x-4\leq 0$

In the first case the solution is the empty set $\emptyset$ . In the second case the solution is the interval $1\leq x \leq 4$ . Now we have that

$A=[1,4]$

$B=(3,5)$

$C=(3,4]$ .

To show that $A\cap B\subseteq C$ consider $x\in A\cap B$ . Then $1\leq x \leq 4\, \text{and}\, 1$ , this implies that $3$ , then $x\in C$ . Now, to show that $C\subseteq A\cap B$ consider $x\in C$ , then $3$ , then $1\leq x \leq 4\, \text{and}\, 3$ , then $x\in [1,4] \, \text{and}\, x\in (3,5)$ , this implies that $x\in A\cap B$ .