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dolphi86 [110]
3 years ago
8

Indicate whether each of the following statements is true of depurination (DP), deamination (DA), or pyrimidine dimer formation

(DF). A given statement may be true of any, all, or none of these processes. This process is caused by spontaneous hydrolysis of a glycosidic bond. This process is induced by ultraviolet light. This can happen to guanine but not to cytosine. This can happen to thymine but not to adenine. This can happen to thymine but not to cytosine. Repair involves a DNA glycosylase. Repair involves an endonuclease. Repair involves DNA ligase. Repair depends on the existence of separate copies of the genetic information in the two strands of the double helix. Repair depends on cleavage of both strands of the double helix.
Biology
1 answer:
solniwko [45]3 years ago
8 0

Answer:

- This process is caused by spontaneous hydrolysis of a glycosidic bond: depurination and deamination

- This process is induced by ultraviolet light:  pyrimidine dimer formation

- This can happen to guanine but not to cytosine: depurination

- This can happen to thymine but not to adenine:  pyrimidine dimer formation

- This can happen to thymine but not to cytosine: none

- Repair involves a DNA glycosylase: deamination

- Repair involves an endonuclease: depurination, deamination and  pyrimidine dimer formation

- Repair involves DNA ligase: depurination, deamination and  pyrimidine dimer formation

-  Repair depends on the existence of separate copies of the genetic information in the two strands of the double helix: depurination, deamination and  pyrimidine dimer formation

- Repair depends on cleavage of both strands of the double helix: none

Explanation:

Depurination is the loss of purine bases (either adenine or guanine), while deamination refers to the removal of an amino group. During depurination, a β-N-glycosidic bond is cleaved by hydrolysis and a nucleic base is released (either adenine or guanine). All DNA bases may undergo deamination, except thymine (since thymine does not have an amino group). The ultraviolet (UV) radiation can cause thymine or cytosine to form dimers (e.g., pyrimidine dimers), being thymine dimers the most common lesion when DNA is exposed to UV light. Pyrimidine dimers may be repaired by different excision mechanisms, e.g., nucleotide excision repair, where the recognition of the DNA damage leads to the removal of the DNA fragment containing the lesion. DNA glycosylases are enzymes involved in the mechanism of base excision, these enzymes recognize and remove damaged bases by hydrolysis of the glycosidic bond, producing an abasic (apurinic and apyrimidinic) site. A DNA ligase enzyme covalently joins two DNA molecules by forming a phosphodiester bond, which is required during these processes.

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How high is the ceiling in a school gym if a volleyball thrown upward from the floor at 15 m/s barely touches the ceiling before
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The height of the ceiling in the school gym from the floor is 11.48m.

HOW TO CALCULATE HEIGHT OF A PROJECTILE:

  • Using one of the equations of motion as follows:

v² = u² + 2as

Where;

v = final velocity (m/s)

u = initial velocity (m/s)

a = gravitational acceleration (m/s²)

s = distance traveled (m)

According to this question,

  • The final velocity (v) of the volleyball is 15m/s
  • The initial velocity is 0m/s
  • The acceleration due to gravity is 9.8m/s

Using the formula, v² = u² + 2as, the height of the ceiling (s) can be calculated as follows:

15² = 0² + 2 (9.8) (s)

225 = 0 + 19.6s

225 = 19.6s

s = 225/19.6

s = 11.48m

Therefore, the height of the ceiling in the school gym from the floor is 11.48m

Learn more: brainly.com/question/21065813

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