Let 2x – y = 3 ——— equation 1
Let x + 5y = 14 ——— equation 2
Making x the subject in eqn 1, = x = y + 3 / 2 ——— eqn 3
• Put eqn 3 in eqn 2
(y + 3 / 2) + 5y = 14
6y = 14 – 3/2
6y = 25/2
y = 25/12
• put y = 25/12 in eqn 3
x = (25/12 + 3/2)
x = 43/12
Answer:
C) 3
Step-by-step explanation:
Answer:
<u>The answer is :</u>
<u>x₁ = 4</u>
<u>x₂ = -4</u>
Step-by-step explanation:
Let's solve the equation using square roots.
X^2+16=0
x² + 16 = 0
x² = -16 (Adding 16 at both sides of the equation)
√x² = i√16 (Square root to both sides of the equation)
x = +/- 4i (Roots of the solution)
<u>x₁ = 4i</u>
<u>x₂ = -4i</u>
There will be a 25 grams left after 3240 years.
The half-life of Radium-226 is 1620 years. If we divide 3240 by 1620 the answer is 2. So that means the amount of Radium-226 will divide in half twice.
100 / 2 = 50 / 2 = 25
Answer:
wow so what's the question then
