Remember
![x^{ \frac{m}{n} }= \sqrt[n]{x^m}](https://tex.z-dn.net/?f=x%5E%7B%20%5Cfrac%7Bm%7D%7Bn%7D%20%7D%3D%20%5Csqrt%5Bn%5D%7Bx%5Em%7D%20)
so
![x^{ \frac{1}{2} }= \sqrt[2]{x^1}](https://tex.z-dn.net/?f=x%5E%7B%20%5Cfrac%7B1%7D%7B2%7D%20%7D%3D%20%5Csqrt%5B2%5D%7Bx%5E1%7D%20)
or √x
so
Look at figure A and figure B on the coordinate plane below.
1 answer:
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Answer:
E(Y) = $0.5
Var(Y) = 14.25
you should pay the same amount $0.5
Step-by-step explanation:
E(Y) = = Σ(YP)
P = probability of each outcomes.
Var(Y) = Σp − (μ x μ)
E(Y) = (2 x 0.25) +(6 x 0.25) + (0.5 x (-3)) = $0.5
Var(Y) = (x 0.25) + (
x 0.25) +(
x 0.5) - (
)
= 14.5 - 0.25
Var(Y) = 14.25
for the difference between the payoff and cost of playing to have mean 0, you should pay the same amount $0.5
Answer:
I) |xz| ≈ 28.6 km
II) |yz| ≈ 34.8 km
Step-by-step explanation:
Let's assume that the position of ship due south of x is z (aà pictor representation of the question is attached)
|xy| = 20 km, |xz| = ?, |yz| = ?, θ(y) = 55°
Using Trigonometric ratio - SOHCAHTOA
I) Tan θ = |xz| ÷ |xy| ⇒ Tan 55° = |xz| ÷ 20
|xz| = 20 * Tan 55 = 20 * 1.428
|xz| = 28.56 km
|xz| ≈ <u>28.6 km</u>
<u />
II) Cos θ = |xy| ÷ |yz| ⇒ Cos 55° = 20 ÷ |yz|
|yz| * Cos 55° = 20 ⇒ |yz| = 20 ÷ Cos 55°
|yz| = 20 ÷ 0.574 = 34.84 km
|yz| ≈ <u>34.8 km</u>
