Answer:
<em>The force that would be applied on the rope just to start moving the wagon is 122 N</em>
Explanation:
Frictional force opposes motion between two surfaces in contact. It is the force that must be applied before a body starts to move. Static friction opposes the motion of two bodies that are in contact but are not moving. The magnitude of static friction to overcome for the body to move can be calculated using equation 1.
F = μ x mg .............................. 1
where F is the frictional force;
μ is the coefficient of friction ( μs, in this case, static friction);
m is mass of the object and;
g is the acceleration due to gravity( a constant equal to 9.81 m/
)
from the equation we are provide with;
μs = 0.25
m = 50 kg
g = 9.81 m/
F =?
Using equation 1
F = 0.25 x 50 kg x 9.81 m/
F = 122.63 N
<em>Therefore a force of 122 N must be applied to the rope just to start the wagon.</em>
The answer is B as all the other options contain quantities not related to describing motion
Answer:149.73 ml
Explanation:
Given

change in volume is given by

![\Delta V=\nu_{initial}\beta _{acetone}\left [ T_f-T_i\right ]](https://tex.z-dn.net/?f=%5CDelta%20V%3D%5Cnu_%7Binitial%7D%5Cbeta%20_%7Bacetone%7D%5Cleft%20%5B%20T_f-T_i%5Cright%20%5D)
![V_{final}=\nu_{initial}+\nu_{initial}\beta _{acetone}\left [ T_f-T_i\right ]](https://tex.z-dn.net/?f=V_%7Bfinal%7D%3D%5Cnu_%7Binitial%7D%2B%5Cnu_%7Binitial%7D%5Cbeta%20_%7Bacetone%7D%5Cleft%20%5B%20T_f-T_i%5Cright%20%5D)
![V_{final}=150+150\times 1.50\times 10^{-4}\left [ 20-32\right ]](https://tex.z-dn.net/?f=V_%7Bfinal%7D%3D150%2B150%5Ctimes%201.50%5Ctimes%2010%5E%7B-4%7D%5Cleft%20%5B%2020-32%5Cright%20%5D)

Nuclear fusion- converts hydrogen atoms into helium. The by-product of nuclear fusion in the Sun's core is a massive volume of energy (solar energy) that gets released and radiates outward toward the surface of the Sun and then into the solar system beyond it.
Answer:
a) 0.3965 j
b) 0.3112 m
Explanation:
The picture attached explains it all. Thank you