That would be false
Hope this helps :)
Exertion is not a good way to describe exercise but there is also alot more words to describe wrong ways for exercise
Answer: B 6.2 Hz
Explanation: Equation for waves v = λf.
Frequency = speed / wavelength f = v/λ
f = 74 m/s / 12 m = 6.166... Hz
It’s C for sure I took this awhile back but I still remember... so thermal equilibrium is when to object have the same temperature due to them touching and transferring temperature for example if we have two metal blocks and one them is hotter than the other when you put them together the heat transfers and makes them both the same temperature.
Principles of conservation of linear momentum
Kinetic Energy before collision 60kJ
Kinetic Energy after collision 56.76kJ
Explanation:
1. Given data
mass m1= 1000kg
velocity u1= 10m/s
mass m2= 800kg
velocity u2= 5m/s
2. We want to find the common velocity after the collision
Applying the principle of conservation of linear momentum for inelastic collision we have
m1u1+m2u2= (m1+m2)V
substituting and solving for V
1000*10+800*5= (1000+800)V
10000+4000= 1800V
14000=1800V
3. Divide both sides by 1800
V= 14000/1800
V= 7.8m/s
4. Now let us find the kinetic energy of the two cars before the collision
For the first car
KE= 1/2m1u1^2
KE= 1/2*1000*10^2
KE=(1000*100)/2
KE= 100000/2
KE= 50000 Joules
KE= 50 kJ
For the second car
KE= 1/2m2u2^2
KE= 1/2*800*5^2
KE=(800*25)/2
KE= 20000/2
KE= 10000 Joules
KE= 10 kJ
Hence the total kinetic energy before the collision is
=50+10
=60kJ
After collision
KE= 1/2m1V^2
KE= 1/2*1000*7.8^2
KE=(1000*60.84)/2
KE= 60840/2
KE= 32420 Joules
KE= 32.42kJ
For the second car
KE= 1/2m2u^2
KE= 1/2*800*7.8^2
KE=(800*60.84)/2
KE= 48.672/2
KE= 24336 Joules
KE= 24.34 kJ
Hence the total Kinetic energy after collision is
=32.42+24.34
=56.76kJ
See the link below for more information on linear momemtum
https://brainly.in/question/17792506