The initial velocity of a car that accelerates at a constant rate of 3m/s² for 5 seconds is 12m/s.
CALCULATE INITIAL VELOCITY:
The initial velocity of the car can be calculated by using one of the equation of motion as follows:
V = u + at
Where;
- V = final velocity (m/s)
- u = initial velocity (m/s)
- a = acceleration due to gravity (m/s²)
- t = time (s)
According to this question, a car accelerates at a constant rate of 3 m/s² for 5 seconds. If it reaches a velocity of 27 m/s, its initial velocity is calculated as follows:
u = v - at
u = 27 - 3(5)
u = 27 - 15
u = 12m/s.
Therefore, the initial velocity of a car that accelerates at a constant rate of 3m/s² for 5 seconds is 12m/s.
Learn more about motion at: brainly.com/question/974124
So first we find the gap between the slits by the formula d=1/N
<span>N is number of lines per metre so 3700 line/cm = 370000 lines/m </span>
<span>So d=2.7*10^-6 </span>
<span>Now we use the formula dsin(angle)=n(wavelength) </span>
<span>d is the same </span>
<span>n is the order of the diffraction pattern </span>
<span>so wavelenth=dsin(angle)/n </span>
<span>=[(2.7*10^-6)*sin30]/3 </span>
<span>=4.5*10^-7 m</span>
Answer:
Explanation:
A magnet has a magnetic field around it which originates at the north pole and enters through the south pole.
In a magnet, like poles will repel each other and unlike poles will attract.
- The north pole of one magnet will repel another north pole of another magnet.
- North pole of one magnet will attract the south pole of another magnet.
- This is the law of attraction and repulsion of magnet.
Answer:
Explanation:
Given
Cannon is fired with a velocity of 
Using Equation of motion
where
after time 
So after 3.3 s cannon ball is at a height of 185.89 m
Answer:
Explanation:
Given
mass of archer 
Average force 
extension in arrow 
Work done to stretch the bow with arrow
This work done is converted into kinetic Energy of arrow
where v= velocity of arrow
(b)if arrow is thrown vertically upward then this energy is converted to Potential energy
