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Mnenie [13.5K]
3 years ago
13

To solve the equation x + 5 = 3x - 4, Jasper graphs the equations f (x) = x + 5 and g(x) = 3x – 4. What is the solution to the e

quation
x + 5 = 3x – 4?​
Mathematics
1 answer:
Phoenix [80]3 years ago
5 0

Answer:

4.5

Step-by-step explanation:

beginning-     x+5=3x-4

combine like terms-     9=2x

divide-   x= 4.5

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Use the given conditions to write an equation for the line in​ point-slope form and general form. Passing through (8 comma negat
miskamm [114]

Answer:

The answer to your question is   y = -5x + 32          point-slope form

                                                      5x + y - 32 = 0      general form

Step-by-step explanation:

Data

(8, -8)

⊥ x - 5y - 6 = 0

Process

1.- Get the slope of the line given

   x - 5y - 6 = 0

   -5y = -x + 6

      y = -x/-5 + 6/-5

      y = x/5 - 6/5

slope = 1/5

slope of the new line -5, because the lines are perpendicular

2.- Get the equation of the new line

          y - y1 = m(x - x1)

          y + 8 = -5(x - 8)

          y + 8 = -5x + 40

          y = -5x + 40 - 8

         y = -5x + 32          point-slope form

Equal to zero to find the general form

         5x + y - 32 = 0      general form

5 0
3 years ago
Let U be the set of natural numbers, A be the set positive odd integers and B be the
alisha [4.7K]

Answer:

Hope it helped u

Step-by-step explanation:

6 0
3 years ago
At the airport, there is a moving walkaway 500 meters long, which moves at a speed of 4 km/hour. Aditya and Ravi step on the wal
Nutka1998 [239]

Answer:

He is approximately 166.6 m ahead of Ravi.

If it's right please mark BRAINLIEST

3 0
2 years ago
Read 2 more answers
What is the value of x?
Phantasy [73]

Answer:

value of x = 5.8 mm

Step-by-step explanation:

We have given,

Two right triangles EDH and EDG.

In right triangle EDH, EH = 56mm , DH = 35 mm

Using Pythagoras theorem we can find ED.

i.e EH² = ED²+DH²

56²=ED²+35²

ED²=56²-35²

ED = √(56²-35²) = 7√39 = 43.71 mm

Now, Consider right triangle EDG

Here, EG=44.8mm , GD = x+4  and ED = 7√39

Again using Pythagoras theorem,

EG² = ED² + DG²

44.8²= (7√39)²+ (x+4)²

(x+4)² = 44.8² - (7√39)²

x+4 = √(44.8² - (7√39)²)

x+4 = 9.8

or x = 9.8 - 4 = 5.8 mm

Hence we got the value of x = 5.8 mm

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3 years ago
Given: N is the midpoint of LQ,
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Answer:

6. SAS Postulate

5. ASA Postulate

Step-by-step explanation:

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