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garri49 [273]
3 years ago
10

Dot patterns can illustrate the Distributive Property. Write a number sentence suggested by the dot patterns below.​

Mathematics
2 answers:
kramer3 years ago
7 0

Answer:

what are the answers or is it a paragrah you have to write

Step-by-step explanation:

Sever21 [200]3 years ago
6 0
A it has to be A because I’dont kno
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First person answers this gets 25 points its khan academy algebra 1
mr Goodwill [35]

a-7=3(b+2)

1. Simplify/Combine like terms

a-7=3b+6

2. Remove a variable

a-7-a=3b+6-a

7=2b+6

3. Isolate the variable

7-6=2b-6

1=2b

4. Divide

1/2=2b/2

b=1/2

1/2g?

8 0
3 years ago
64x-16 I need 3 equivalent expressions
Daniel [21]

Answer:

8 (8x - 2)

(64) x X - 16

4 (16 x- 4)

Step-by-step explanation:

6 0
2 years ago
If y=e5t is a solution to the differential equation
a_sh-v [17]

Answer:

k = 30, y(t) = C_1e^{5t}+C_2e^{6t}

Step-by-step explanation:

Since y=e^{5t} is a solution, then it must satisfy the differential equation. So, we calculate the derivatives and replace the value in the equation. We have that

\frac{d^2y}{dt^2} = 25 e^{5t},\frac{dy}{dt} = 5e^{5t}

Then, replacing the derivatives in the equation we have:

25e^{5t}-11(5)e^{5t}+ke^{5t}=0 e^{5t}(25-55+k) =0

Since e^{5t} is a positive function, we have that

25-55+k = 0 \rightarrow k = 30.

Now, consider a general solution y(t) = Ae^{rt}, A \in \mathbb{R}, then, by calculating the derivatives and replacing them in the equation, we get

Ae^{rt}(r^2-11r+30)=0

We already know that r=5 is a solution of the equation, then we can divide the polynomial by the factor (r-5) to the get the other solution. If we do so, we get that (r-6)=0. So the other solution is r=6.

Therefore, the general solution is

y(t) = C_1e^{5t}+C_2e^{6t}

8 0
3 years ago
Please help :( really stuck on this and don’t understand please attempt to do it .
kenny6666 [7]
Answer) That graph is not a function
Explanation) The graph that you provided is not a function. It does not pass the vertical line test. The vertical line test is when you draw a vertical line (l) at any point on the graph and it should touch 1 or less parts of the graph. If you put the line at x=1, the vertical line only touches the graph at (1,8.5) but if you put the line at x=5, it touches (5,1) and (5,8.5) so it does not pass the test. You should be able to put the line anywhere and have it touch ONLY 1 point. There cannot be multiple of the same x values.
3 0
3 years ago
Marcus is selling t-shirts at the State Fair. He brings 200 shirts to sell. He has long-sleeve and short-sleeved T-shirts for sa
saveliy_v [14]
Let x = number of long sleeve shirts Let y = number of short sleeve shirts x + y = 200 x/2 + y/3 = 80 Now solve this pair of simultaneous equations to find x and y.
5 0
3 years ago
Read 2 more answers
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