Answer:
8 one-dollar bills
3 five-dollar bills
2 ten-dollar bills
Step-by-step explanation:
Let x = # of one-dollar bills, y = # of five-dollar bills, and z = # of ten-dollar bills. Total amount in the wallet is $43, so the first equation would be 1x + 5y + 10z = 43. Next, there are 4 times as many one-dollar bills as ten-dollar bills, so x = 4z. There are 13 bills in total, so x + y + z = 13
x + 5y + 10z = 43
x = 4z
x + y + z = 13
x + 5y + 10z = 43
x + 0y - 4z = 0
x + y + z = 13
5y + 14z = 43
-y - 5z = -13
5y + 14z = 43
-5y - 25z = -65
-11z = -22
z = 2
x = 4z
x = 4*2 = 8
x + y + z = 13
8 + y + 2 = 13
10 + y = 13
y = 3
Answer:
Step-by-step explanation:
Amplitude is twice the coefficent of the sine function. In this case, 
Period is 
divided by the coefficent of x, in this case, 
Phase shift, is how much you sum or subctract from x inside the sine, in this case 
.
Midline you get by hiding the sine and reading what's left, in this case, -4.
Answer:
x = 53
Step-by-step explanation:
The sum of the angle measures in a triangle is 180°:
91° + 36° + x° = 180°
x° = 180° -127° = 53°
x = 53
Answer:
To see how these fractions are equal, I divided the numerators by the denominators. For instance, you could have 4 over 5 (4/5) and divide 4 by 5 (4/5) to get 0.8. Now you'll do the same thing for the fractions given
24/45=0.533...
8/15=0.533...
48/90=0.533...
5/9=0.5556
As you can see, the only fraction that doesn't equal 0.53, or the outlier, is 5/9 or 0.5556
Step-by-step explanation:
Using the z-distribution, it is found that the 90% confidence interval is given by: (0.6350, 0.6984).
<h3>What is a confidence interval of proportions?</h3>
A confidence interval of proportions is given by:
In which:
is the sample proportion.
In this problem, we have a 90% confidence level, hence
, z is the value of Z that has a p-value of 
, so the critical value is z = 1.645.
The sample size and the estimate are given by:
Hence, the bounds of the interval are given by:
The 90% confidence interval is given by: (0.6350, 0.6984).
More can be learned about the z-distribution at brainly.com/question/25890103
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