Answer:
part 1 : y = x^2 + 3x + 5
y = x + 13
solution:
x^2 + 3x + 5 = x + 13
x^2 + 2x -8 = 0
(x+4)(x-2) = 0
x = -4 or x = 2
if x = -4, y = 9
if x = 2 , y = 15
part 2 : x^2 + 2x + 1 = 0
(x + 1)^2 = 0
x = -1
y = 1
task 2
part 1 : Let our two digit number be 26
Next, we rewrite it as a difference of two numbers
26=32-6
We want to square 26 using the identity:
In this case,
x=32
y=6
Substituting into the identity
plz make me brainliest
Answer:
the one with 3/10 left has more
Step-by-step explanation:
because 1/5 is equal to 2/10 and 3/10>2/10
Answer:
64x
Step-by-step explanation:
because 4 * 2 is in parenthesis, that means you multiply 8x by them.
8x (4*2)
8x (8)
64x
Basically with the example you have you need to have the x and y variables on different sides.
Equation:
-18x+9y=72 (now you want to add 18x on both sides)
<u>+18x +18x
</u><u>9y=72+18x </u> (next you divide 9 to both sides to get x and y alone)
9
y=8+2x (now that you have the x and y alone this is the final equation)
On the graph you want to put a dot on 8 since it's the y-intercept or the starting point of the equation. After that you want to add 2 every time you go by 1 on the x-axis. I have a picture of a graph...
<em>I hope this help you out :D</em>