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Pavel [41]
3 years ago
9

PLZ HELP,, WILL BE MUCH APPRECIATED!

Mathematics
1 answer:
docker41 [41]3 years ago
7 0

Answer:

178cm

Step-by-step explanation:

x=180

y=160

0.4(x+y)+42 =

0.4(180 + 160) +42 =

0.4(340)+42=

136+42=

178cm

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I need to know the answer and how to solve this
AURORKA [14]

Answer:

135

Step-by-step explanation:

subtract 180 by 45 since a line is 180, that is what you get for the angle that is adjacent to angle 2, there is a rule if it is adjacent, they equal each other. thus, angle 2 is 135

5 0
2 years ago
A clock was reading the time accurately on Friday at noon. On Monday at 6pm the clock was running late by 468 seconds. On averag
Setler [38]

The clock was skipping 3 seconds every 30 minutes from Friday noon to Monday 6 pm.

The clock was still accurate by Friday noon. The clock was late by 468 seconds by Monday, 6 pm.

To solve the problem, we must:

Know how many 30-minutes have passed during the time period.

1 day = 24 hours

1 hour = 60 minutes = 2 × (30 minutes)

1 day = 24 hours × 2 × (30 minutes)

1 day = 48 × (30 minutes)

Thus, there are 48, 30-minutes in a day. On Friday, however, we start counting at noon, which is half of the day. Moreover, on Monday, the mark is only up to 6 pm, which is three-fourths of the day.

Friday = 48 × \frac{1}{2} = 24

Saturday = 48

Sunday = 48

Monday = 48 × \frac{3}{4} = 36

TOTAL = 24 + 48 + 48 + 36 = 156

Therefore, the total number of 30-minutes that have passed is 156. There were 156, 30-minutes that passed during the time period.

Divide the number of total seconds late by the number of 30-minutes passed.

That is, the number of total seconds late= 468 seconds ÷ 156

= 3 seconds  

Therefore, the clock was skipping 3 seconds every 30 minutes from Friday noon to Monday 6 pm.

To learn more about clock problems visit:

brainly.com/question/27122093.

#SPJ1

3 0
2 years ago
 PLEASE HELP!! A tennis ball machine serves a ball vertically into the air from a height of two feet, with an initial speed of 1
ch4aika [34]
Thank you for posting your question here. I hope the answer below will help. 

Vo=110 feet per second 
<span>ho=2 feet </span>
<span>So, h(t) = -16t^2 +110t +2 </span>
<span>Take the derivative: h'(t) = 110 -32t </span>
<span>The maximum height will be at the inflection when the derivative crosses the x-axis aka when h'(t)=0. </span>
<span>So, set h'(t)=0 and solve for t: </span>
<span>0 = 110 -32t </span>
<span>-110 = -32t </span>
<span>t=3.4375 </span>
<span>t=3.44 seconds </span>
4 0
3 years ago
Read 2 more answers
I need help pls!!!!!​
svp [43]

Answer:

AP EURO DBQ RUBRIC. Updated July 2017. Name: DBQ: CONTEXTUALIZATION. Describes a broader historical context

4 0
2 years ago
PLZ HELP! Need this QUICK! Thx so much! (
Semenov [28]

Answer:

2, 5, 8

Step-by-step explanation:

5 0
3 years ago
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