I'd suggest you get rid of the fraction first. Mult. every term by 3. You will get
3y^2 + 10y + 3 = 0
From inspection, with coefficient a=3 and coeff. c = 3, the binomial factors could possibly begin with y or 3y: for example, y+1; also, the binom. factors may end in +1. Let's try the possible binomial factor 3y + 1.
Note that 10y separates into 9y+1y.
Then 3y^2 + 10y + 3 = 0 becomes
3y^2 + 9y + 1y + 3 = 0
Let's apply factoring by grouping:
3y^2 + 9y + 1y + 3 = 0
3y*(y + 3) + 1(y + 3) so y+3 is indeed a common factor.
Factoring y+3 out, we get (y+3)(3y + 1), which prove to be the correct set of factors. Multiply these together to ensure that the product is indeed y^2 + (10/3)y + 1.
Answer:
step by step below
Step-by-step explanation:
3. AB --> EF (53°)
BC --> DE (37°)
AC --> DF (90°)
4. EF/AB = 8/4 = 2 (scale factor)
5. DE = 2 x CB = 6
6. FD = √6²+8² = √100 = 10
<h3>
<u>Explanation</u></h3>
- Solve the equation for s-term.

- Answer Check by substituting s = -10 in the equation.

<u>No</u><u> </u><u>Solutions</u>
When both sides of equation are different. For example, 3 = 4 which makes the equation false. That means the equation is false for all real numbers, thus having no solutions.
<u>One</u><u> </u><u>Solution</u>
A common type solution because you see this type of solution a lot. If you can solve the equation for a variable like x = 2 or s = 0. That's one solution.
<u>Infinitely</u><u> </u><u>Many</u><u> </u><u>Solutions</u>
When both sides are same like 3 = 3 or 7 = 7. That means the equation is true for all real numbers. You can see this type of solution by solving the equation with same both sides like 3x+2 = 3x+2.
<h3>
<u>Answer</u></h3>
- Because we can solve the equation for s-term. Therefore the answer is <u>one</u><u> </u><u>solution</u>
I’m sure you’ll find some who can