Question

A cube has a surface are of 54. What's the volume?

Answer 1

Given Information :

• Surface area of cube = 54 sq. units

To find :

• Volume

Calculation :

We know that,

$\bigstar \: \boxed{\sf {Volume_{(Cube)} = (\ell)^3}}$

• l = length of side

Let's find out the side first. We know that,

$\bigstar \: \boxed{\sf {T.S.A_{(Cube)} = 6\ell^2}}$

According to the question,

$\longmapsto \sf {54 = 6\ell^2 }$

$\longmapsto \sf {\dfrac{54}{6} = \ell^2 }$

$\longmapsto \sf {9 = \ell^2 }$

$\longmapsto \sf {\sqrt{9} = \ell }$

$\longmapsto \sf \red{3 \: units = \ell }$

Now, calculating volume :

$\bigstar \: \boxed{\sf {Volume_{(Cube)} = (\ell)^3}}$

→ Volume = l × l × l

→ Volume = 3 × 3 × 3

→ Volume = 27

Option B is correct.

Answer 2

Answer:

B

Step-by-step explanation:

54/6=9 meaning each face has an area of 9.

Meaning each side has an area of 3.

That means the volume is 3*3*3=27