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ankoles [38]
3 years ago
6

What class is sodiumtrioxocarbonate(IV) strong or weak base and why?​

Chemistry
1 answer:
aev [14]3 years ago
5 0

Answer:

Strong Base

Explanation:

sodiumtrioxocarbonate(IV) Na2CO3 exists in various forms such as; an anhydrous form or in a crystalline form. Usually, the manufacturing process of sodiumtrioxocarbonate(IV) Na2CO3 is known as the Solvay process.

Now, upon reaction, Na2CO3 reacts to yield CO⁻₃. That appears to be a conjugate base of a weak acid. Thus, the occurrence of the removal of H⁺ resultt into Carbonic acid, i.e. a Strong Base.

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In which material are the particles arranged in a regular geometric pattern?
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6 0
3 years ago
A baby weighs 7 pounds, 4 ounces at birth and 7 pounds, I ounce at discharge. What percent of weight did the baby lose
Aloiza [94]

Answer:

2.6%

Explanation:

As, 1 ounce (oz) =  0.0625 pounds (lb)

Therefore, weight of baby at discharge = 7 lb,1 oz = 7+0.0625 lb = 7.0625 lb

Since, 1 oz =  0.0625 lb

⇒ 4 oz = 4×0.0625 = 0.25 lb

Therefore, weight of baby at birth = 7 lb,4 oz = 7+0.25 lb = 7.25 lb

The <u>amount of weight lost</u> is equal to the difference of weight of the baby at birth and discharge.

Therefore, <u>weight lost</u> = 7.25 lb - 7.0625 lb = <u>0.1875 lb</u>

Now, the <u>percentage of weight lost</u> by the baby is given by the amount of weight lost divided by the weight of the baby at birth.

Therefore, <u>the percentage of weight los</u>t = weight lost ÷ weight at birth = 0.1875 lb ÷ 7.25 lb × 100 = <u>2.6% </u>

6 0
4 years ago
Answer with explanation
creativ13 [48]
The answer should be:

KOH (aq) + HCl (aq) --> KCl (aq) + H20 (l).

KOH is a base, because OH can accept a H+.
HCl is an acid because it can donate a H+.

In general, bases are : OH-, and acids are : H+.


8 0
3 years ago
How do buffers work in the human body
Elodia [21]
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</span>
5 0
3 years ago
An important reaction in the formation of photochemical smog is the photodissociation of NO2: NO2 + hv &gt;&gt;&gt; NO(g) + O(g)
vaieri [72.5K]

Explanation:

NO_2 + hv\rightarrow NO(g) + O(g)

The maximum wavelength of light that can cause this reaction is 420 nm.

a) The wavelength given lies in the range of visible light range that is from 400 nano meters to 700 nano meters.

The light with wavelength of 420 nm is found in the range of visible light.

b)The maximum strength of a bond :

E=\frac{h\times c}{\lambda}

where,

E = energy of photon = Energy required to break single molecule of nitrogen dioxide

h = Planck's constant = 6.626\times 10^{-34}Js

c = speed of light = 3\times 10^8m/s

\lambda = wavelength = 420 nm=420\times 10^{-9}m

E=\frac{6.626\times 10^{-34}Js\times 3\times 10^8 m/s}{420\times 10^{-9}m}

E=4.733\times 10^{-19} J

Energy required to break 1 mole of nitrogen dioxide molecules:

= E\times N_A=4.733\times 10^{-19} J\times 6.022\times 10^{23} mol^{-1}

=285,012.66 J/mol=285.13 kJ/mol

(1 J = 0.001 kJ )

285.13 is the maximum strength of a bond, in kJ/mol, that can be broken by absorption of a photon of 420-nm light.

c) the photodissociation reaction showing Lewis-dot structures is given in an image attached.

6 0
4 years ago
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