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aleksandr82 [10.1K]
3 years ago
12

What is the molariity of a 50.0 mL aqueous solution containing 10.0 grams of copper (II) sulfate, CuSO4?

Chemistry
1 answer:
jolli1 [7]3 years ago
3 0

Answer:

The molarity is 1.26 \frac{ moles}{L}

Explanation:

Molarity is a unit of concentration that is based on the volume of a solution and represents the number of moles of solutes contained in a liter. The molarity of a solution is calculated by dividing the moles of the solute by the liters of the solution and is expressed in units (moles / liter).

Molarity=\frac{number of moles of solute}{Volume}

You must calculate the number of moles of CuSO₄. So, being:

  • Cu: 63.54 g/mole
  • S: 32 g/mole
  • O: 16 g/mole

the molar mass of CuSO₄ is

CuSO₄=63.54 g/mole + 32 g/mole + 4* 16 g/mole= 159.54 g/mole

Then it is possible to apply the following rule of three: if 159.54 g of CuSO₄ are present in 1 mole, 10 g in how many moles are they?

moles=\frac{10 g*1 mole}{159.54 g}

moles= 0.063 moles

Then:

  • number of moles of solute= 0.063 moles
  • Volume= 50 mL= 0.05 L (Being 1L=1000 mL)

Replacing in the definition of molarity:

Molarity=\frac{0.063 moles}{0.05 L}

Molarity= 1.26 \frac{ moles}{L}

<u><em>The molarity is 1.26 </em></u>\frac{ moles}{L}<u><em></em></u>

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Answer:

Speed, v = 5 m/s

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2 years ago
How many moles are in 272 grams of hydrogen peroxide (H2O2) ?
Strike441 [17]

Answer:

8 moles

Explanation:

When we are asked to convert from grams of a substance into moles, we have to use the substance's molar mass.

Meaning that for this problem, we'll <em>use the molar mass of hydrogen peroxide</em> (H₂O₂), as follows:

  • 272 g ÷ 34 g/mol = 8 mol

There are 8 moles in 272 grams of hydrogen peroxide.

7 0
2 years ago
Calculate the molality of 75.0 grams of MgCl2 (molar mass=95.21 g/mol) dissolved in 500.0 g of solvent.
nordsb [41]

<u>Answer:</u> The molality of magnesium chloride is 1.58 m

<u>Explanation:</u>

To calculate the molality of solution, we use the equation:

\text{Molality}=\frac{m_{solute}\times 1000}{M_{solute}\times W_{solvent}\text{ (in grams)}}

Where,

m_{solute} = Given mass of solute (magnesium chloride) = 75.0

M_{solute} = Molar mass of solute (magnesium chloride) = 95.21 g/mol  

W_{solvent} = Mass of solvent = 500.0 g

Putting values in above equation, we get:

\text{Molality of }MgCl_2=\frac{75.0\times 1000}{95.21\times 500.0}\\\\\text{Molality of }MgCl_2=1.58m

Hence, the molality of magnesium chloride is 1.58 m

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Board instances involving eligibility or disciplinary issues that are addressed by a board-approved order public records and accessible on the BON's web page.

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7 0
2 years ago
How many molecules are there in 2.30g of NH3
Vinil7 [7]

Answer:

8.13x10^22 molecules

Explanation:

We can use the Avogadro's number(6.022 x 10^23 units / mole)

2.30 g NH3 (1 mol / 17.03 g ) (6.022 x 10^23 molecules / 1 mol ) = 8.13x10^22 molecules

Hope this helps! Feel free to ask any questions!

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