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2 years ago

Express 0.00386×10-4 in standard form?(Urgent....Answer if sure)

Mathematics

1 answer:

bekas [8.4K]2 years ago

4 0

Answer:

0.000000386

Step-by-step explanation:

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Marianna [84]

30 + 70 + D = 180
100 + D = 180
D = 80°

7 0

2 years ago

4.8.4 Raw materials are studied for contamination. Suppose that the number of particles of contamination per pound of material i

forsale [732]

Answer:

700 lbs and 3.742

Step-by-step explanation:

Given that raw materials are studied for contamination. Suppose that the number of particles of contamination per pound of material is a Poisson random variable with a mean of 0.02 particle per pound.

a) To get 14 particles of contamination we must have

expected number of pounds = $\frac{14}{0.02} \\=700$

b) Since for 700 pounds particles expected are 14 we can say in a Poisson distribution mean and variance are equal

i.e. Var (700 lbs to obtain 14 particles of contamination ) = 14

Std deviation = $\sqrt{14} =3.742$

5 0

3 years ago

Please help<br> y=-3x + 5 if y>-1

xenn [34]

Answer:

y = -3x +5. if y>-1

Step-by-step explanation:

-1 < -3x + 5

-6 < -3x

x < 2

4 0

3 years ago

How do I solve 1 1/3 × 2 2/4 is steps?

Lina20 [59]

Answer:

40/12 or 3 1/3

Step-by-step explanation:

To multiply mixed numbers, first change any mixed number to an improper fraction. Then multiply the numerators together and the denominators together

1 1/3 as an improper fraction is 4/3 and 2 2/4 as an improper fraction is 10/4.

4*10=40

3*4=12

5 0

3 years ago

In a large population, 71 % of the people have been vaccinated. If 4 people are randomly selected, what is the probability that

Oksi-84 [34.3K]

Answer:

The answer is "0.9929"

Step-by-step explanation:

$\text{The distribution in binomials is n = 4 and p = 0.71.}\\\\\text{Vaccinated Pr(AT LEAST ONE) = 1-pr( no people vaccinated ).}$

$= 1 - Bin (n=4, k =0, p=0.71) \\\\= 1 - C(4,0) \times 0.71^0 \times (1-0.71)^{4-0} \\\\= 1 - (1 \times 0.29^4)$

$= 1 - (1 \times 0.00707281)\\\\=0.9929$

5 0

3 years ago