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3 years ago

What principle will amount to $35000 if invested at 6.5% compounded quarterly for 5 year?

Mathematics

1 answer:

Anastaziya [24]3 years ago

7 0

Answer:

bye

Step-by-step explanation:

You might be interested in

Find the equation of the line The line has a slope of 1.3 and passes through the point (-2.3, -3.2)

irga5000 [103]

Answer:

y=1.3 x - 0.21

Step-by-step explanation:

$y = (slope) \times x + (constant)$

set (-2.3,-3.2) in above

$- 3.2 = 1.3 \times ( - 2.3) + c$

then c=-0.21

3 0

2 years ago

If I have a 62% in a class, what percentage do I need to get on a 50% weighted test grade to have at least a 70% in the class?

Nastasia [14]

Answer:

78%

Step-by-step explanation:

70 = 0.50 (62) + 0.50 (x)

70 = 31 + 0.5x

39 = 0.5x

x = 78

You must get at least a 78% on the test to have at least 70% in the class.

3 0

3 years ago

Rewrite this percent as a decimal:<br> 80%

ella [17]

Answer:

.80

0.80

Step-by-step explanation:

80 is out of 100, which is other words is .80 or 0.80

6 0

3 years ago

Which is an equation of the line with a slope of 2/3 passing through the point (4,-1)?

Bond [772]

Answer:

y=2/3x-11/3

Step-by-step explanation:

to find the y intercept, you can input your values into the equation:

b=y1−m⋅x1

When you do that, you get:

b=−1−(2/3)⋅(4)=−11/3

When you convert that equation into y=mx+b form, you get:

y=2/3x-11/3

Please mark Brainliest ;)

3 0

2 years ago

Which of the following is a solution to the following system of inequalities?

iren2701 [21]

Option D: $(0,3)$ is the solution to the inequalities.

Explanation:

From the given graph, we can see that the equation of the inequalities are

$y>-x+1$ and $y\leq 2 x+3$

To determine the coordinate that satisfies the inequality, let us substitute the coordinates in both of the inequalities $y>-x+1$ and $$y$

Thus, we have,

Option A: $(1,-1)$

Substituting the coordinates in $y>-x+1$ and $y\leq 2 x+3$ , we get,

$y>-x+1\implies-1>0$ is not true.

$$y\leq 2 x+3 \implies -1\leq 5$ is true.

Since, only one equation satisfies the condition, the coordinate $(1,-1)$ is not a solution.

Hence, Option A is not the correct answer.

Option B: $(-4,0)$

Substituting the coordinates in $y>-x+1$ and $y\leq 2 x+3$ , we get,

$y>-x+1\implies0>5$ is not true.

$$y\leq 2 x+3 \implies 0\leq -5$ is not true.

Since, both the equations does not satisfy the condition, the coordinate $(-4,0)$ is not a solution.

Hence, Option B is not the correct answer.

Option C: $(3,-2)$

Substituting the coordinates in $y>-x+1$ and $y\leq 2 x+3$ , we get,

$y>-x+1\implies-2>-2$ is not true.

$$y\leq 2 x+3 \implies -2\leq 9$ is true.

Since, only one equation satisfies the condition, the coordinate $(3,-2)$ is not a solution.

Hence, Option C is not the correct answer.

Option D: $(0,3)$

Substituting the coordinates in $y>-x+1$ and $y\leq 2 x+3$ , we get,

$y>-x+1\implies3>1$ is true.

$$y\leq 2 x+3 \implies 3\leq 3$ is true.

Since, both equation satisfies the condition, the coordinate $(0,3)$ is a solution.

Hence, Option D is the correct answer.

4 0

3 years ago