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MAVERICK [17]
3 years ago
12

Rewrite this percent as a decimal: 80%

Mathematics
1 answer:
ella [17]3 years ago
6 0

Answer:

.80

or

0.80

Step-by-step explanation:

80 is out of 100, which is other words is .80 or 0.80

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A circular flower bed is 19 m in diameter and has a circular sidewalk around it that is 4 m wide. Find the area of the sidewalk
yaroslaw [1]

Answer:

289 m²

Step-by-step explanation:

First find the area of the flower bed

A=πr²= (3.14)(9.5)² = 283.385

Then get the area of everything including the sidewalk

A=πr²= (3.14)(13.5)² = 572.265

Then subtract and you'll get the area of just the sidewalk

572.265 - 283.385 = 288.88m²

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3 years ago
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Suppose that an individual has a body fat percentage of 16.8% and weighs 152 pounds. How many pounds of his weight is made up of
natka813 [3]
<h3>Answer: 25,5 p</h3>

Step-by-step explanation:

  • 16 , 8 % = ? p
  • 100% = 152 p

  • \pmb {? =\dfrac{152\cdot 16, 8}{100}=25, \underline 536 p\approx25,5  p  }
4 0
2 years ago
Amount of sugar in a sugar bowl is 0.75 cups
Mariana [72]
I equals 70 grams cup because
4 0
3 years ago
Which algebraic expression is equivalent to the expression below?
77julia77 [94]
6(3x + 4) + 5(12-x) simplifies to

D) 13x + 84

3 0
3 years ago
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Assume the readings on thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. Find the pro
lisov135 [29]

Answer:

0.0326 = 3.26% probability that a randomly selected thermometer reads between −2.23 and −1.69.

The sketch is drawn at the end.

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 0°C and a standard deviation of 1.00°C.

This means that \mu = 0, \sigma = 1

Find the probability that a randomly selected thermometer reads between −2.23 and −1.69

This is the p-value of Z when X = -1.69 subtracted by the p-value of Z when X = -2.23.

X = -1.69

Z = \frac{X - \mu}{\sigma}

Z = \frac{-1.69 - 0}{1}

Z = -1.69

Z = -1.69 has a p-value of 0.0455

X = -2.23

Z = \frac{X - \mu}{\sigma}

Z = \frac{-2.23 - 0}{1}

Z = -2.23

Z = -2.23 has a p-value of 0.0129

0.0455 - 0.0129 = 0.0326

0.0326 = 3.26% probability that a randomly selected thermometer reads between −2.23 and −1.69.

Sketch:

3 0
3 years ago
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