Find two consecutive odd integers the sum of whose squares is 130.
1 answer:
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Answer:
product of the roots= c/a
Step-by-step explanation:
The the two roots(α and β) of the quadratic equation ax²+bx+c=0 as given by shridharacharya formula are
now product of the roots
αβ= ×
use formula (a+b)(a-b)= a^2-b^2 and solve we get
αβ= c/a
therefore product of the roots= c/a