Answer:
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Step-by-step explanation:
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Complete question
A 29-meter ladder is sliding down a vertical wall so the distance between the top of the ladder and the ground is decreasing at 7 meters per minute. At a certain instant, the bottom of the ladder is 21 meters from the wall.
What is the rate of change of the distance between the bottom of the ladder and the wall at that instant(in meters per minute)
Answer:

Step-by-step explanation:
From the question we are told that
Slant height 
Change in Vertical height 
Horizontal length 
Generally in finding the distance form the top to the bottom of the wall it is mathematically given by




Generally solving for the differential equation is mathematically represented as







deion has the following data: 47, u, 41, 38. if the range is 10 which could "U" be ?
REmember that
The range of a set of data is the difference between the highest and lowest values in the set
If U is the highest value
Range=U-38
range=10
so
10=U-38
U=10+38
U=48
If U is the lowest value
Range=47-U
10=47-U
U=47-10
U=37
therefore
U coulbe between 48 and 37
Answer:
The correct answer is A) 5n = 3d and 3n + 6 = 2d + 4
Step-by-step explanation:
hope this is right...
Answer:
45x³
Step-by-step explanation:
Given
3x × 15x²
= 3 × 15 × x × x²
= 45 × x³
= 45x³