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Harman [31]
3 years ago
5

What is force?

Physics
1 answer:
jeyben [28]3 years ago
4 0
Here i hope this helps, let me know if you need clarification on anything :)

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Seagrasses are flowering plants. Forty-nine species in 12 genera are known. The flowers are simple and open underwater; pollen i
Harrizon [31]

i just took the test and its c

8 0
4 years ago
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14. Why is it cooler to wear a white shirt than a black shirt on a hot, sunny day?
zzz [600]

Answer:

White or lighter colored, shirt REFLECTS most of the visible wavelengths or all colors of light while a black or dark shirt ABSORBS more wavelengths.

So, Absorbed radiation is converted into heat, making the darker or black shirt warmer to wear.

 

<u>-TheUnknownScientist</u><u> 72</u>

7 0
3 years ago
A mass of 10.0 kg is in a gravitational field of 3.50 N/kg. What force acts on the mass?
mash [69]

Answer:

Force=35 N

Explanation:

Given data

mass m=10.0 kg

Gravitational field E=3.50 N/kg

To find

Force

Solution

From definition of gravitational field intensity.

E_{gravitational-field }=\frac{Force}{mass}\\  E=F/m\\F=mE\\F=(10.0 kg)*(3.50 N/kg)\\F=35N

6 0
4 years ago
Read 2 more answers
Please Help me to find the answer...​
KonstantinChe [14]

Answer:

1. S-S Repulsion           N-S Attraction

2. S-N Attraction          N-N Repulsion

Explanation:

1. S-S Repulsion           N-S Attraction

2. S-N Attraction          N-N Repulsion

3 0
3 years ago
Three polarizing filters are stacked, with the polarizing axis ofthe second and third filters at angles of 22.2^\circ and 68.0^\
andreev551 [17]

Answer:

I₂ = 25.4 W

Explanation:

Polarization problems can be solved with the malus law

     I = I₀ cos² θ

Let's apply this formula to find the intendant intensity (Gone)

Second and third polarizer, at an angle between them is

    θ₂ = 68.0-22.2 = 45.8º

    I = I₂ cos² θ₂

    I₂ = I / cos₂ θ₂

    I₂ = 75.5 / cos² 45.8

    I₂ = 155.3 W

We repeat for First and second polarizer

   I₂ = I₁ cos² θ₁

   I₁ = I₂ / cos² θ₁

   I₁ = 155.3 / cos² 22.2

   I₁ = 181.2 W

Now we analyze the first polarizer with the incident light is not polarized only half of the light for the first polarized

    I₁ = I₀ / 2

   I₀ = 2 I₁

   I₀ = 2 181.2

   I₀ = 362.4 W

Now we remove the second polarizer the intensity that reaches the third polarizer is

    I₁ = 181.2 W

The intensity at the exit is

    I₂ = I₁ cos² θ₂

    I₂ = 181.2 cos² 68.0

   I₂ = 25.4 W

8 0
4 years ago
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