You can describe kinetic energy and the potential energy of motion to get your answer.
<span>The answer to your question: <span>The
sun emits shortwave radiation, but it is radiated back off of planetary bodies
as longwave radiation. </span></span>
<span>
Explanation: The sun emits shortwave
radiation, wherein it’s extremely hot and is filled with more energy compared
to the radiation emitted by planets. This also comes in the form of light. However, once this becomes absorbed by planetary bodies, it turns into longwave radiation. A good example is the earth’s atmosphere emitting energy
(longwave radiation), which is energy originally coming from the sun (shortwave radiation).</span>
Answer:
125.5J
Explanation:
Given parameters:
Mass of the bowling ball = 6.1kg
Height of lifting = 2.1m
Unknown:
Increase in the ball energy = ?
Solution:
The ball has changed position by moving it from one point to another. So, it has acquired more potential energy.
Potential energy = mgh
m is the mass
g is the gravity
h is the height
Now insert the given parameters and solve;
Potential energy = 6.1 x 9.8 x 2.1 = 125.5J
The answer to question one is A.
The answer to question two is A.
The answer to question three is D.
Answer:
ΔU = 5.21 × 10^(10) J
Explanation:
We are given;
Mass of object; m = 1040 kg
To solve this, we will use the formula for potential energy which is;
U = -GMm/r
But we are told we want to move the object from the Earth's surface to an altitude four times the Earth's radius.
Thus;
ΔU = -GMm((1/r_f) - (1/r_i))
Where;
M is mass of earth = 5.98 × 10^(24) kg
r_f is final radius
r_i is initial radius
G is gravitational constant = 6.67 × 10^(-11) N.m²/kg²
Since, it's moving to altitude four times the Earth's radius, it means that;
r_i = R_e
r_f = R_e + 4R_e = 5R_e
Where R_e is radius of earth = 6371 × 10³ m
Thus;
ΔU = -6.67 × 10^(-11) × 5.98 × 10^(24)
× 1040((1/(5 × 6371 × 10³)) - (1/(6371 × 10³))
ΔU = 5.21 × 10^(10) J
