The ball is moving at a constant speed of 0.5 m/s for 2.3 seconds how far does it go?

8.0kg rocket fired horizontally encounters a force of air resistance of 4.9 N. The force supplied by the rocket's engine is 60.9

Gelneren [198K]

60.9 - 4.9= 56
56 is the net force
using the formula F = ma
56= 8a
a = 7
acceleration is 7ms^-2

6 0

3 years ago

If the index of refraction of a medium is 1.4, determine the speed of light in that medium.

Damm [24]

The speed of light in that medium is $2.14 \times 10^8 \ m/s$ .

<u>Explanation:</u>

It is known that the light's speed is constant when it travels in vacuum and the value is $3 \times 108 m/s$ . When the light enters another medium other than vacuum, its speed get decreased as the light gets refracted by an angle.

The amount of refraction can be determined by the index of refraction or refractive index of the medium. The refraction index is measured as the ratios of speed of light in vacuum to that in the medium. It is represented as η = $\frac {c}{v}$

So, here η is the index of refraction of a medium which is given as 1.4, c is the light's speed in vacuum ( $3 \times 10^8 ms^-^1$ ) and v is the light's speed in that medium which we need to find.

$1.4= \frac{(3 \times 10 ^ 8)} {v}$

$v= \frac {(3 \times 10^8)}{1.4} =2.14 \times 10^8 \ m/s$

Thus the speed of light in that medium is $2.14 \times 10^8 \ m/s.$

3 0

3 years ago

How many poles do you expect to see in your magnet? Look around your room. Make a list of 5 items that might be attracted to the

jeyben [28]

Answer:

1.1 Two poles: North and South Poles.

1.2 - Staple pin - Nail - Tip of my phone charger - Metal keys - Cloth Hanger

1.3 - Wooden bed cot - Plastic pen - Game pad - Wooden shelf - Paper - A T-shirt

1.4 Yes

1.5 No

5 0

3 years ago

A student plucks a fixed-end string, creating a standing wave with 6.00 nodes (including any nodes at the ends). The string is t

Vesna [10]

1) 2.5 wavelengths

2) 0.208 m

3) 1731 Hz

Explanation:

1)

Standing waves are waves that do not propagate, but instead the particles of the medium just oscillate around a fixed position. Examples of standing waves are the waves produced on a string with fixed ends.

The points of a standing wave in which the amplitude of the oscillation is always zero are called nodes.

The two fixed ends of the string are two nodes. In this problem, we have a total of 6 nodes along the string: this means that there are 4 additional nodes apart from the two ends of the string.

Therefore, this also means that the string oscillate in 5 different segments.

One wavelength is equal to 2 segments of the oscillation: therefore, since here there are 5 segments, this means that the number of wavelengths that we have in this string is

$n=\frac{5}{2}=2.5$

2)

The wavelength of a wave is the distance between two consecutive crests (or throughs) of the wave.

The wavelength of a standing wave can be also measured as the distance between the nth-node and the (n+2)-th node: so, basically, the wavelength in a standing wave is twice the distance between two nodes:

$\lambda = 2 d$