You are given the molarity of the solution which is 1x10-5 M. Since molarity is moles of solute over liters solution. You could determines the moles.
M=m/V
1x10-5 = m/(2 L)
m = 2x10-5 moles ligand A
We could determine the mass of ligand A by using the molar weight:
2x10-5 mol * 250 g/mol = 0.005 grams of ligand A
I hope I was able to answer your question. Have a good day.
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