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Aleks [24]
3 years ago
14

Eugene and Jill are selling wrapping paper for a school fundraiser. Customers can buy rolls of plain wrapping paper and rolls of

shiny wrapping paper. Eugene sold 3 rolls of plain wrapping paper and 11 rolls of shiny wrapping paper for a total of $168. Jill sold 10 rolls of plain wrapping paper and 11 rolls of shiny wrapping paper for a total of $252. What is the cost each of one roll of plain wrapping paper and one roll of shiny wrapping paper?
Mathematics
1 answer:
Roman55 [17]3 years ago
4 0

Answer:

let p = cost of 1 plain wrapping paper

let h = cost of 1 shiny rolls wrapping paper

Write an equation for each statement,

" Eugene sold 3 rolls of plain wrapping paper and 11 rolls of shiny wrapping paper for a total of $168 "

<em>3</em><em>p</em><em> </em><em>+</em><em> </em><em>1</em><em>1</em><em>h</em><em> </em><em>=</em><em> </em><em>$</em><em>1</em><em>6</em><em>8</em><em> </em>

<em>Jill </em><em> sold </em><em>1</em><em>0</em><em> </em><em> rolls of plain wrapping paper and 1</em><em>1</em><em> </em><em>rolls</em><em> of </em><em>shiny </em><em> wrapping paper for a total of </em><em>$</em><em>2</em><em>5</em><em>2</em><em>."</em>

<em>1</em><em>0</em><em>p + 1</em><em>1</em><em>h = </em><em>$</em><em>2</em><em>5</em><em>2</em><em> </em>

Use elimination here,

10p + 11h = $252

3p + 11h = $168

subtraction eliminates h, find p

7p = $84

p = 84/7

p = $12 for wrap of plain paper

Find h using the 1st original equation

3(12) + 11h = 168

36+ 11h = 168

11h = 168 - 36

11h = 132

h = 132/11

h = $12 for shiny wrapping paper

Therefore each plain wrapping paper costs $12 and each shiny wrapping paper costs same $12 !

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