Answer:
Matt will need 10176 square quilts to cover the wall
Step-by-step explanation:
To answer this perfectly, we will have to first convert everything to the same unit.
dimensions of the quilt squares = 3 inches
Length of the wall = 1 yard = 36 inches
Breadth of the wall = 212 feet = 2544 inches.
The next step, is to find the area of the wall that Matt is covering.
Area of wall = length X breadth = 36 X 2544 = 
We will also find the area of the square quilts. This is given as length X length =
=
to get the number of square quilts that will cover that area, we will have to divide the area of the wall by the area of the quilts
= 91584 /9 = 10176 quilts
Matt will need 10176 quilts to cover the wall
Answer:
If you're looking for H it could be 6
Step-by-step explanation:
bc 6/3+16=18 so 6/3=2 so 2+16=18
Answer:
-25/36
Step-by-step explanation:
-5/6 x 5/6 = -25/36
There is no way to simplify it.
You just needed to multiply the deniminators and the numerators. And since you can't simplity -25/36, you have your answer.
The answer to your Q the better one it is the 4- pound bag because it coast less money
Answer:
a. h = 60t − 4.9t²
b. 12.2 seconds
c. 183.7 meters
Step-by-step explanation:
a. Given:
y₀ = 0 m
v₀ = 60 m/s
a = -9.8 m/s²
y = y₀ + v₀ t + ½ at²
h = 0 m + (60 m/s) t + ½ (-9.8 m/s²) t²
h = 60t − 4.9t²
b. When the ball lands, h = 0.
0 = 60t − 4.9t²
0 = t (60 − 4.9t)
t = 0 or 12.2
The ball lands after 12.2 seconds.
c. The maximum height is at the vertex of the parabola.
t = -b / (2a)
t = -60 / (2 × -4.9)
t = 6.1 seconds
Alternatively, the maximum height is reached at half the time it takes to land.
t = 12.2 / 2
t = 6.1 seconds
After 6.1 seconds, the height reached is:
h = 60 (6.1) − 4.9 (6.1)²
h = 183.7 meters