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3 years ago

Step 6: Measure Pressure and Volume with the Book and 1 kg of Weight

Chemistry

2 answers:

goldfiish [28.3K]3 years ago

7 0

Answer:

Starting from the top

1.498

1.18

43.5

51.3

For step 7

2.498

1.27

40.5

51.4

For 8

3.498

1.37

37.5

51.4

For 9

4.498

1.47

35.0

51.5

Lmk if anyone needs earlier steps, but I'm going to assume no since you're already on 6

Explanation:

Mashcka [7]3 years ago

3 0

Answer:

For Step 5:

0.498

1.08

47.5

51.3

It goes in this order. Hope this helps

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An insulated piston-cylinder device contains 1 L of saturated liquid water at pressure of 150 kPa. An electric resistance heater

miskamm [114]

Answer:

Explanation:

In this problem,

we will determine the enthalpy at the end of heat input and we get the condition is the super heated state.

so the entropy change will be due to latent heat at 150 kPa and also due to temperature change at the super heated state.

All the temperature, enthalpy is evaluated with the help of the steam table.

mass is calculated with the help of a specific volume at initial condition.

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2 years ago

Using standard heats of formation, calculate the standard enthalpy change for the following reaction. 2NH3(g) 3N2O(g)4N2(g) 3H2O

trasher [3.6K]

Answer: $\Delta H^{0} = -879.15 kJ/mol$

Explanation: Heats of formation is the amount of heat necessary to create 1 mol of a compound from its molecular constituents. The basic conditions the substance is formed is at standard conditions: 1 atm and 25°C. Each compound has its own heat of formation per mol of compound (kJ/mol), but to an element is assigned a value of zero.

Standard Enthalpy Change is defined as the heat absorbed or released when a reaction takes place. It can be positive or negative, which means reaction is endothermic or exothermic, respectively.

Enthalpy change is calculated as the difference between the sum of heat formation of products and the sum of heat formation of the reactants:

$\Delta H^{0}=\Sigma H^{0}_{f}_{(products)}-\Sigma H^{0}_{f}_{(reactants)}$

For the reaction

2NH₃ + 3N₂O → 4N₂ + 3H₂O

2(-46.2) + 3(82.05) 4(0) + 3(-241.8)

$\Delta H^{0}=3(-241.8)-[ 2(-46.2)+3(82.05)]$

$\Delta H^{0}=-725.4-153.75$

$\Delta H^{0}=-879.15$

The standard enthalpy change for the reaction is $\Delta H^{0}=-879.15$ kJ

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2 years ago

What is cellulose and what does it do?

olga2289 [7]

Answer:

Cellulose is an organic compound with the formula , a polysaccharide consisting of a linear chain of several hundred to many thousands of β linked D-glucose units. Cellulose is an important structural component of the primary cell wall of green plants, many forms of algae and the oomycetes.

Explanation:

8 0

3 years ago

Read 2 more answers

How many moles of MgS2O3 are in 201g of the compound?

Tamiku [17]

divide the 201g by the mol mass of the compound. Just add up the masses of the various element

8 0

3 years ago

Which of the statements below is not a characteristic of economically developed nations?

nikklg [1K]

I would go with option #4, reduced use of resources!

:V