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3 years ago

Step 6: Measure Pressure and Volume with the Book and 1 kg of Weight

Chemistry

2 answers:

goldfiish [28.3K]3 years ago

7 0

Answer:

Starting from the top

1.498

1.18

43.5

51.3

For step 7

2.498

1.27

40.5

51.4

For 8

3.498

1.37

37.5

51.4

For 9

4.498

1.47

35.0

51.5

Lmk if anyone needs earlier steps, but I'm going to assume no since you're already on 6

Explanation:

Mashcka [7]3 years ago

3 0

Answer:

For Step 5:

0.498

1.08

47.5

51.3

It goes in this order. Hope this helps

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What color are the universal indicators for: HCl, Na3CO3, NaOH, H20

Ierofanga [76]

HCl - Red (strong acid)
$Na_{2} CO_{3}$ - Blue (weak base)
NaOH - Purple (strong base)
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3 years ago

2) Show the calculation of Kc for the following reaction if an initial reaction mixture of 0.800 mole of CO and 2.40 mole of H2

nadezda [96]

Answer:

Kc = 3.90

Explanation:

CO reacts with $H_2$ to form $CH_4$ and $H_2O$ . balanced reaction is:

$CO(g) + 3H_2 (g) \leftrightharpoons CH_4(g) + H_2O(g)$

No. of moles of CO = 0.800 mol

No. of moles of $H_2$ = 2.40 mol

Volume = 8.00 L

Concentration = $\frac{Moles}{Volume\ in\ L}$

Concentration of CO = $\frac{0.800}{8.00} = 0.100\ mol/L$

Concentration of $H_2$ = $\frac{2.40}{8.00} = 0.300\ mol/L$

$CO(g) + 3H_2 (g) \leftrightharpoons CH_4(g) + H_2O(g)$

Initial 0.100 0.300 0 0

equi. 0.100 -x 0.300 - 3x x x

It is given that,

at equilibrium $H_2O (x)$ = 0.309/8.00 = 0.0386 M

So, at equilibrium CO = 0.100 - 0.0386 = 0.0614 M

At equilibrium $H_2$ = 0.300 - 0.0386 × 3 = 0.184 M

At equilibrium $CH_4$ = 0.0386 M

$Kc=\frac{[H_2O][CH_4]}{[CO][H_2]^3}$

$Kc=\frac{0.0386 \times 0.0386}{(0.184)^3 \times 0.0614} =3.90$

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Copper carbonate (CuCO3) reacts with hydrochloric acid (HCl) according to this equation:

mihalych1998 [28]

Answer:

Explanation:

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3 years ago

Read 2 more answers

Problem 3.100 a chemical plant uses electrical energy to decompose aqueous solutions of nacl to give cl2,h2, and naoh: 2nacl(aq)

chubhunter [2.5K]

First we calculate the number of moles of Cl2, that is:

moles Cl2 = 1.5*10^10 grams/71 grams/mol = 211267605.633802817 mol = 2.1 * 10 ^ 8 mole = x <span>

So that based on stoichiometry, the number of moles of NaOH = 2x and that of H2 = x mol

mass of NaOH = 4.2*10^8 * 40 =168*10^8 grams = 1.68 * 10^6 kg = 1.68 metric tons

<span>mass of H2 = 2.1*10^8 * 2 = 4.2*10^8 grams = 0.042 * 10^6 kg = 0.042 metric tons.</span></span>

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3 years ago