i can not understand the question. There seems to be missing info
In order to make a buffer that was 2 pH away from the pka, what you have to do is to dilute the buffer.
<h3>How to dilute the buffer.</h3>
If the buffer was made using a base and an acid, then there can be an adjustment through the use of hydrochloric acid.
It can also be adjusted to the value that you want through the use of base such as sodium hydroxide
Read more on buffer here:brainly.com/question/22390063
The concentration of this acid in moles per litre : 17.41
<h3>Further explanation</h3>
Given
99.5% acetic acid
density=ρ=1.05 g/ml
Required
the concentration (mol/L)
Solution
99.5% dan density 1.05 g/ml (MW acetic acid = 60 g/mol)
Answer:
particles in 2 moles.
Explanation:
The number of particles that are contained in one mole, the international unit of amount of substance: by definition, exactly 6.022×10²³, and it is dimensionless. It is named after the scientist Amedeo Avogadro.
It is also known as Avogadro's constant.
∴ Number of particles in one mole =
∴ Number of particles in 2 mole = 2 times Number of particles in one mole
∴ Number of particles in 2 mole=
Hence there are particles in 2 moles.
Moles = Molarity x Volume
Moles = 2.0 x 0.50
= 1.0 mole
hope this helps!