Answer:
I would say the answer is b.
Explanation:
The nurse<span> is </span>caring<span> for a </span>client<span> with a temperature of 104.5 degrees Fahrenheit. A health </span>care provider<span> prescribes 500 mg of an antibiotic intravenous While undergoing a soapsuds </span>enema, theclient reports abdominal<span> cramping.</span>
If you mean periodic table, then it's metals
<span>Part A:
Molar mass luminol = 177g/mol
10g = 10/177 = 0.0565 mol Luminol
Dissolved in 75mL solution = 0.075L
Molarity = 0.0565/0.075 = 0.753M solution
Part B.
There should be no problem with this part If .0L contains 3.0*10^-2 mol Luminol, then 2.0L will contain 2*3.0*10^-2 = 6.0*10^-2 mol
Part C:
Use equation:
M1V1 = M2V2
0.753 *V1 = (3.0*10^-2) * 1000
V1 = 30/0.753
V1 = 39.8 mL of stock solution contains 3.0*10^-2 mol Luminol.</span>
