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ioda
4 years ago
8

Brenda assumed that if the bank was willing to give her a loan, she could afford to make the monthly payments. This is an exampl

e of _____.
a misconception
a long-term goal
being financially irresponsible
being financially responsible
Mathematics
2 answers:
zhenek [66]4 years ago
8 0

Answer:

being financially responsible

Step-by-step explanation:

ycow [4]4 years ago
5 0

Answer:

a misconception

Step-by-step explanation:

I think it's a misconception because she just assumed, which means she dousn't really know.

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The median of the data is 3

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3 years ago
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Part A: Let x and y be the number of persons attending the two-day conference and y be the number of vouchers released. The equation that would best express the given is,
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Part B: The number of people attending the conference is determined by dividing the given number of vouchers by 4. The answer is 956. 
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3 years ago
What is the area of a triangle with a base of 2.4 cm and a height of 0.8 cm?
Andrej [43]
The easiest way to find the area of a triangle is by doing 1/2 base x height. So halve the base, 2.4 / 2 = 1.2. Now do 1.2 x 0.8. Which equals 0.96.
6 0
3 years ago
Match each interval with its corresponding average rate of change for q(x) = (x + 3)2. 1. -6 ≤ x ≤ -4 1 2. -3 ≤ x ≤ 0 -4 3. -6 ≤
MrMuchimi
The average rate of change of a function f(x) in an interval, a < x < b is given by
\frac{f(b) - f(a)}{b - a}

Given q(x) = (x + 3)^2

1.) The average rate of change of q(x) in the interval -6 ≤ x ≤ -4 is given by \frac{q(-4)-q(-6)}{-4-(-6)} = \frac{(-4+3)^2-(-6+3)^2}{-4+6} = \frac{1-9}{2} = \frac{-8}{2} =-4

2.) The average rate of change of q(x) in the interval -3 ≤ x ≤ 0 is given by \frac{q(0)-q(-3)}{0-(-3)} = \frac{(0+3)^2-(-3+3)^2}{0+3} = \frac{9-0}{3} = \frac{9}{3} =3

3.) The average rate of change of q(x) in the interval -6 ≤ x ≤ -3 is given by \frac{q(-3)-q(-6)}{-3-(-6)} = \frac{(-3+3)^2-(-6+3)^2}{-3+6} = \frac{0-9}{3} = \frac{-9}{3} =-3

4.) The average rate of change of q(x) in the interval -3 ≤ x ≤ -2 is given by \frac{q(-2)-q(-3)}{-2-(-3)} = \frac{(-2+3)^2-(-3+3)^2}{-2+3} = \frac{1-0}{1} = \frac{1}{1} =1

5.) The average rate of change of q(x) in the interval -4 ≤ x ≤ -3 is given by \frac{q(-3)-q(-4)}{-3-(-4)} = \frac{(-3+3)^2-(-4+3)^2}{-3+4} = \frac{0-1}{1} = \frac{-1}{1} =-1

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3 0
3 years ago
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The coordinates of AB are A(-5, -1) and B(-2, -6). If AC : CB = 3 : 7, what are the coordinates of point C?
navik [9.2K]

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Coordinates of the point C is: (-4.1, -2.5)

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