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Aliun [14]
2 years ago
5

Circumference (rounding) Your gonna need to round to the nearest tenth.

Mathematics
2 answers:
enyata [817]2 years ago
8 0

Answer:

60.95 or 61msquared

Step-by-step explanation:

OleMash [197]2 years ago
5 0

Answer:60.9

Step-by-step explanation:

use the formula circumference= 2(pi)(radius)

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Morgarella [4.7K]

Answer:

a=48 units^2

Step-by-step explanation:

The area of a rectangle can be found using:

a=bh

We know the base is 6, and the height is 8, so we can substitute them in

a=6*8

a=48

Area uses units squared, so,

a=48 units^2

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Answer:

15

Step-by-step explanation:

5 divided by 1/3 is the same as if you flip the denominator meaning 5 x 3 which is 15

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How do you write 652% as a fraction, mixed number, or whole number?
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2 years ago
16. Solve -3x2 - 9x + 12 = 0.
AURORKA [14]

Given :

  • -3x² - 9x + 12 = 0

To find :-

  • Value of x .

Solution :-

Given equation ,

  • -( 3x² + 9x -12 ) = 0
  • 3x² + 9x - 12 = 0
  • 3x² + 12x - 3x - 12 = 0
  • 3x ( x +4) -3( x +4) = 0
  • (3x -3)(x +4) = 0
  • x = 3/3 , -4
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7 0
2 years ago
A rectangular swimming pool is twice as long as it is wide. A small concrete walkway surrounds the pool. The walkway is a 2 feet
Ksivusya [100]

Answer:

The width and the length of the pool are 12 ft and 24 ft respectively.

Step-by-step explanation:

The length (L) of the rectangular swimming pool is twice its wide (W):

L_{1} = 2W_{1}

Also, the area of the walkway of 2 feet wide is 448:

W_{2} = 2 ft

A_{T} = W_{2}*L_{2} = 448 ft^{2}

Where 1 is for the swimming pool (lower rectangle) and 2 is for the walkway more the pool (bigger rectangle).

The total area is related to the pool area and the walkway area as follows:

A_{T} = A_{1} + A_{w}    (1)          

The area of the pool is given by:

A_{1} = L_{1}*W_{1}        

A_{1} = (2W_{1})*W_{1} = 2W_{1}^{2}  (2)          

And the area of the walkway is:

A_{w} = 2(L_{2}*2 + W_{1}*2) = 4L_{2} + 4W_{1}    (3)          

Where the length of the bigger rectangle is related to the lower rectangle as follows:                  

L_{2} = 4 + L_{1} = 4 + 2W_{1}   (4)        

By entering equations (4), (3), and (2) into equation (1) we have:

A_{T} = A_{1} + A_{w}

A_{T} = 2W_{1}^{2} + 4L_{2} + 4W_{1}                

448 = 2W_{1}^{2} + 4(4 + 2W_{1}) + 4W_{1}            

224 = W_{1}^{2} + 8 + 4W_{1} + 2W_{1}

224 = W_{1}^{2} + 8 + 6W_{1}

By solving the above quadratic equation we have:

W₁ = 12 ft

Hence, the width of the pool is 12 feet, and the length is:

L_{1} = 2W_{1} = 2*12 ft = 24 ft

Therefore, the width and the length of the pool are 12 ft and 24 ft respectively.

I hope it helps you!                                                                                          

8 0
2 years ago
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