Answer:
Cu(s) + 2AgNO3(aq)→Cu(NO3)2(aq)+2Ag(s)
This chemical equation means:
One mole of solid copper plus two moles of aqueous silver nitrate produce one mole of copper(II) nitrate plus two moles of solid silver.
This is a single replacement reaction in which the metal copper replaces the metal silver.
Answer:
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Explanation:
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Answer:
CaCO₃(s) → CaO(s) + CO₂(g)
Explanation:
The decomposition reaction always make two compounds from one.
The products always have simpler chemical structure, originated from a determined compound. This can happens spontaneously or by a third party.
A notable example of decomposition is hydrolysis. As for example the case of water, which decomposes and generates oxygen and hydrogen gas
2H₂O (l) → 2 H₂ (g) + O₂ (g)
In this case, the calium carbonate decomposes into CaO and CO₂
These two, are the products of the decomposition.
Of course, the unique reactant is the Calcium Carbonate
The balanced equation is:
CaCO₃(s) → CaO(s) + CO₂(g)
Assuming the concentration of stock solution is 50% sodium phosphate buffer solution, the volume of stock solution required is 6 mL and the volume of water required is 6 mL.
<h3>What volume of a stock Sodium phosphate buffer and water is needed to 12 mL of 25% sodium phosphate buffer of pH 4?</h3>
The process of preparing solutions from stock solutions of higher concentration is known as dilution.
Dilution is done with the aid of the dilution formula given below:
where
- C1 is the concentration of stock solution
- V1 is the volume of stock solution required to prepare a diluted solution
- C2 is the concentration of the diluted solution prepared
- V2 is the final volume of the diluted solution
From the data provided:
C1 is not given
V1 is unknown
C2 = 25%
V2 = 12 mL
- Assuming C1 is 50% solution
Volume of stock, V1, required is calculated as follows:
V1 = C2V2/C1
V1 = 25 × 12 /50
V1 = 6 mL
Therefore, the volume of stock solution required is 6 mL and the volume of water required is 6 mL.
Learn more about dilution formula at: brainly.com/question/7208546
Answer: The unknown solution had the lower concentration
Explanation: concentration will always move from higher to lower region. If the concentration of the unknown solution has increased, it therefore means that the initial concentration of the unknown solution was low
