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Jobisdone [24]
3 years ago
14

Briefly explain formality in solution.

Chemistry
1 answer:
Zielflug [23.3K]3 years ago
4 0

Answer:

Both molarity and formality express concentration as moles of solute per liter of solution. Formality is a substance's total concentration in solution without regard to its specific chemical form. ... The formality of a solution is defined as the number of formula mass of any solute dissolved in 1 litre of solution.

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Which solution below has the highest concentration of hydroxide ions?a. pH= 3.21b. pH= 7.00c. pH= 7.93d. pH= 12.59e. pH= 9.82
Sloan [31]

Answer:

  • <em>The solution that has the highest concentration of hydroxide ions is </em><u>d. pH = 12.59.</u>

Explanation:

You can solve this question using just some chemical facts:

  1. pH is a measure of acidity or alkalinity: the higher the pH the lower the acidity and the higher the alkalinity.
  2. The higher the concentration of hydroxide ions the lower the acidity or the higher the alkalinity of the solution, this is the higher the pH.

Hence, since you are asked to state the solution with the highest concentration of hydroxide ions, you just pick the highest pH. This is the option d, pH = 12.59.

These mathematical relations are used to find the exact concentrations of hydroxide ions:

  • pH + pOH = 14 ⇒ pOH = 14 - pH

  • pOH = - log [OH⁻] ⇒ [OH^-]=10^{-pOH}

Then, you can follow these calculations:

Solution    pH        pOH                            [OH⁻]

a.               3.21       14 - 3.21 = 10.79        antilogarithm of 10.79 = 1.6 × 10⁻¹¹

b.               7.00      14 - 7.00 = 7.00        antilogarithm of 7.00 = 10⁻⁷

c.                7.93      14 - 7.93 = 6.07        antilogarithm of 6.07 = 8.5 × 10⁻⁷

d.               12.59     14 - 12.59 = 1.41        antilogarithm of 1.41 = 0.039

e.               9.82      14 - 9.82 = 4.18        antilogarithm of 4.18 = 6.6 × 10⁻⁵

From which you see that the highest concentration of hydroxide ions is for pH = 12.59.

5 0
2 years ago
Molecular formula for C4H10
Gnesinka [82]
I think this is what you mean:

    H H H H
H-C-C-C-C-H
    H H H H

OR 

<span>CH3CH2CH2CH3
</span>
If not, clarify and I will be happy to help.
6 0
3 years ago
Under certain conditions Argon gas diffuses at a rate of 3.2 cm per second under the same conditions an unknown gas diffuses at
kozerog [31]

Answer:

20 g/mol

Explanation:

We can use <em>Graham’s Law of diffusion</em>:

The rate of diffusion (<em>r</em>) of a gas is inversely proportional to the square root of its molar mass (<em>M</em>).

r = \frac{1 }{\sqrt{M}}

If you have two gases, the ratio of their rates of diffusion is

\frac{r_{2}}{r_{1}} = \sqrt{\frac{M_{1}}{M_{2}}}

Squaring both sides, we get

(\frac{r_{2}}{r_{1}})^{2} = \frac{M_{1}}{M_{2}}

Solve for <em>M</em>₂:

M_{2} = M_{1} \times (\frac{r_{1}}{r_{2}})^{2}

M_{2} = \text{39.95 g/mol} \times (\frac{\text{3.2 cm/s}}{\text{4.5 cm/s}})^{2}= \text{39.95 g/mol} \times (0.711 )^{2}

= \text{39.95 g/mol} \times 0.506 = \textbf{20 g/mol}

7 0
2 years ago
a mass of mercury occupies 0.350 l. what volume would an equal mass of ethanol occupy? the density of mercury is 13.546 g/ml and
Fed [463]

The density told you the mass covered by one unit of volume of that substance.

Density defines how perfectly the molecules of a substance are packed in a unit of volume.

In the given problem the substances are expressed in g/ml which means that a unit of volume will be 1 mL.

Given ,

Density of mercury = 13.546 g/ml

It means 1mL of mercury will have a mass of 13.546 g, Similarly 1 mL of ethanol will have a mass of 0.789 g.

0.350 L * 10^3 ml/1 L* 13.546/1 mL = 4,741.1 g

The volume of ethanol will have an equal mass is

4741.1 g* 1 mL/0.789g = 6,008.9 mL

6,008.9 mL* 1L/10^3mL = 6.0081 L

Hence the answer is 6.0081 L

To know more about density occupies here :

brainly.com/question/18518241?referrer=searchResults

#SPJ4

8 0
1 year ago
A compound of carbon and hydrogen having one double covalent bond between two of the carbon atoms in the molecule is known as wh
Alexandra [31]
It would be known as a meth_(insert - ane, - ene, and -yne) hydrocarbon. 1 bond = -ane 2 bonds = - ene And so on.
7 0
3 years ago
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