Explanation:
It is known that stronger is the bonding between the atoms of a molecule more difficulty it will face to form vapors. Hence, more heat needs to be provided to the molecule. As a result, it will have high boiling point.
So, in heptanol there is hydrogen bonding. Hence, there is strong bonding so, boiling point of heptanol will be high.
On the other hand, heptane has long carbon chain as compared to pentane. Therefore, heptane will occupy more surface area and thus, more heating will be provided to it. Hence, boiling point of heptane will be greater than the boiling point of pentane.
Thus, we can conclude that rank of given compounds according to start of their boiling point is as follows.
pentane < heptane < heptanol
Density = Mass / Volume
Density = 2.74g / 3.10cm³
Density = 0.88 g/cm³
Answer: 2, you divide the value by 1000, so... 2000/1000 = 2.
1) Use the fact that 1 mol of gas at STP occupies 22.4 liter
=> 1 mol / 22.4 l = x / 0.125 l => x = 0.125 l * 1 mol / 22.4 l = 0.00558 mol
2) Now use the molar mass of the gas
molar mass of CO2 ≈ 44 g / mol
Formula: molar mass = mass in grams / number of moles =>
mass in grams = molar mass * number of moles = 44 g/mol * 0.00558 moles
mass = 0.246 g
Answer: 0.246 g