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enot [183]
3 years ago
15

Synthesis of propionic acid

Chemistry
2 answers:
Karolina [17]3 years ago
5 0

Answer:

H2C=CH2 + H2O + CO → CH3CH2CO2H. It is also produced by the aerobic oxidation of propionaldehyde.

astra-53 [7]3 years ago
3 0

Answer:

H2C=CH2 + H2O + CO → CH3CH2CO2H. It is also produced by the aerobic oxidation of propionaldehyde.

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What elements are highlighted:<br> a. Nonmetals<br> b. Metals<br> C. Metalloids
Advocard [28]
Non metals
(It’s both halogens and noble gases ) the other ones which are white(not highlighted) are alkali metals, alkaline earth metals, and transition metals :3
6 0
3 years ago
Which of the following is always a reactant in a combustion reaction? (5 points)
aleksandr82 [10.1K]

Answer:

A

Explanation:

Combustion reaction always has something hydrocarbon plus oxygen gas which equals to carbon dioxide and water. Always being a reactant in a combustion reaction is oxygen, since reactants are what we start off the reaction with.

4 0
2 years ago
Show that, with appropriate coefficients, the two reactions can be summed to give the overall oxidation of SO2 by O2 to give SO3
SIZIF [17.4K]

Answer:

See explanation

Explanation:

We know that the process of the oxidation of SO2 to SO3 is catalysed by NO2 gas. It occurs in two stages and i will show the balanced reaction equation of the both stages below;

Step 1

2NO2(g) + 2SO2(g) ------> 2NO(g) + 2SO3(g)

Step 2

2NO(g) + O2(g) -------> 2NO2(g)

So, the overall reaction equation is;

2SO2(g) + O2(g) ------> 2SO3(g)

5 0
3 years ago
If you had excess aluminum, how many moles of aluminum chloride could be produced from 28.0 g of chlorine gas, Cl2?
Mice21 [21]

Answer:

Yes chemistry. Try to add then multiply the top. Get the moles and you will find it.

Explanation:

Try to add then multiply the moles in the equation

6 0
3 years ago
The maximum allowable concentration of pb2+ ions in drinking water is 0.05 ppm (i.e., 0.05 g of pb2+ in 1 million grams of water
trasher [3.6K]
PbSO₄ partially dissociates in water. the balanced equation is;
                    
                       PbSO₄(s) ⇄  Pb²⁺(aq) + SO₄²⁻(aq)
Initial                                     -                -
Change             -X               +X           +X
Equilibrium                           X              X

Ksp           =    [Pb²⁺(aq)] [SO₄²⁻(aq)]
1.6 x 10⁻⁸  =    X * X
1.6 x 10⁻⁸  =    X²
          X    =   1.3 x 10⁻⁴ M
      
Hence the Pb²⁺ concentration in underground water is 1.3 x 10⁻⁴ M. 
[Pb²⁺]  = 1.3 x 10⁻⁴ M.
           = 1.3 x 10⁻⁴ mol / L x 207 g / mol 
           = 26.91 ppm

8 0
3 years ago
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