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3 years ago

Please help the correct awnser gets brainlist

Mathematics

1 answer:

Artyom0805 [142]3 years ago

7 0

Answer:

Answer is D)14

Step-by-step explanation:

if u convert 3 1/2 into an improper fraction then it should look lie 7/2 the multiply that by 4 which equal 28/2 then divide that and it will equal 14

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Can some one please help me will give 94 points for it

NNADVOKAT [17]

You can solve this by using "similar triangles".

In triangle ABC, we are looking for side AC which is x. Side AC is similar to side DF in triangle EDF.

You can solve for side x by picking two sides in triangle ABC and their corresponding sides in triangle EDF. This is what I mean:
$\frac{AC}{BC} = \frac{DF}{EF}$
Substitute for the values of AC, BC, DF and EF:
$\frac{x}{4} = \frac{11}{8} \\ \\ 8x = 4 \times 11 \\ \\ x = \frac{44}{8}$
$x = 5.5 \: units$
To solve for y, do the same thing. Pick two sides on triangle ABC and their corresponding sides in triangle DEF.
$\frac{AB}{BC} = \frac{DE}{EF}$
Substitute for the values and solve:
$\frac{3}{4} = \frac{y}{8}$
$4y = 24 \\ \\ y = 6 \: units$

We have the value x to be 5.5 units and y to be 6 units.

7 0

2 years ago

Read 2 more answers

A. i. Write down the 2 x 2 matrix. R, corresponding to a reflection in the origin

lisov135 [29]

Answer:

Step-by-step explanation:

that was easy

7 0

2 years ago

The distance between the point (2,1,1) and the plane x-2y=5 is

Eduardwww [97]

The given plane has normal vector

$x-2y=5\implies\mathbf n=\langle1,-2,0\rangle$

Scaling n by a real number t gives a set of vectors that span an entire line through the origin. Translating this line by adding the vector <2, 1, 1> makes it so that this line passes through the point (2, 1, 1). So this line has equation

$\mathbf r(t)=\langle1,-2,0\rangle t+\langle2,1,1\rangle=\langle 2+t, 1-2t, 1\rangle$

This line passes through (2, 1, 1) when t = 0, and the line intersects with the plane when

$x-2y=5\implies(2+t)-2(1-2t)=5\implies5t=5\implies t=1$

which corresponds the point (3, -1, 1) (simply plug t = 1 into the coordinates of $\mathbf r(t)$ ).

So the distance between the plane and the point is the distance between the points (2, 1, 1) and (3, -1, 1):

$\sqrt{(2-3)^2+(1-(-1))^2+(1-1)^2}=\boxed{\sqrt5}$

7 0

3 years ago

Z varies jointly with x and y.

Elan Coil [88]

First, let's find "k" the constant of variation:

z= k.x.y (since z varies jointly with x and y)

60 =k.(2).(3) → 60 = 6k and k =10, So z = 10x.y

z= 10(4)(9) = 10(36) and z = 360

3 0

2 years ago

Help I have to submit it

siniylev [52]

The answer is C

Hope that helps

3 0

2 years ago