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max2010maxim [7]
3 years ago
13

What is x. pls help me​

Mathematics
2 answers:
ehidna [41]3 years ago
8 0
The answer might be 40
34kurt3 years ago
5 0
The answer would be 40 because that’s a 90 degree angles it’s in
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Hi could someone just help me with this I'm not sure if i'm doing it correctly.
salantis [7]
Two angles are supplementary when they <span>add up to 180 degrees </span>⇒
m∠1 + m∠2 = 180°
4y + 7 + 9y + 4 = 180
13y + 11 = 180
13y = 180 - 11
13y = 169
y = 169/13
y = 13

m∠2 = 9y + 4 = 9 * 13 + 4 = 121°
4 0
3 years ago
Find the slope of a<br> line with ordered pairs<br> (1,5) and (5,8)
klemol [59]

Step-by-step explanation:

(1,5) (5,8)

x,y. x,y

Formula: <u>y2-y1</u>

x2-x1

so...

<u>8-5</u><u>=</u> <u>3</u>

5-1 = 4

so... <u>3</u>

4

6 0
2 years ago
Bryan is asked to write an inequality to represent the graph.
Fittoniya [83]

The error that Bryan has done in this inequality is that he included –14 in his solution set.

<h3>How to point out the mistake made</h3>

What Bryan has to do would be to write this inequality in such a way that the variable would appear on the left.

But the symbol that he has chosen does not move in this same direction as the graph.

The -14 should not be inclusive in the graph because it is not a part of the graph solution.

He used the wrong number in this inequality.

Read more on inequalities here:

brainly.com/question/24372553

#SPJ1

7 0
2 years ago
PLEASE HELP I GIVE BRAINLIEST
RoseWind [281]

can u take a better pic :) so its more clear!!

Step-by-step explanation:

4 0
2 years ago
Let X1, X2 and X3 be three independent random variables that are uniformly distributed between 50 and 100.
sergejj [24]

Answer:

a) the probability that the minimum of the three is between 75 and 90 is 0.00072

b) the probability that the second smallest of the three is between 75 and 90 is 0.396

Step-by-step explanation:

Given that;

fx(x) = { 1/5 ; 50 < x < 100

              0, otherwise}

Fx(x) = { x-50 / 50 ; 50 < x < 100

                          1 ;   x > 100

a)

n = 3

F(1) (x) = nf(x) ( 1-F(x)^n-1

= 3 × 1/50 ( 1 - ((x-50)/50)²

= 3/50 (( 100 - x)/50)²

=3/50³ ( 100 - x)²

Therefore P ( 75 < (x) < 90) =  ⁹⁰∫₇₅ 3/50³ ( 100 - x)² dx

= 3/50³ [ -2 (100 - x ]₇₅⁹⁰

= (3 ( -20 + 50)) / 50₃

= 9 / 12500 = 0.00072

b)

f(k) (x) = nf(x)  ( ⁿ⁻¹_k₋ ₁) ( F(x) )^k-1 ; ( 1 - F(x) )^n-k

Now for n = 3, k = 2

f(2) (x) = 3f(x) × 2 × (x-50 / 50) ( 1 - (x-50 / 50))

= 6 × 1/50 × ( x-50 / 50) ( 100-x / 50)

= 6/50³ ( 150x - x² - 5000 )

therefore

P( 75 < x2 < 90 ) = 6/50³ ⁹⁰∫₇₅ ( 150x - x² - 5000 ) dx

= 99 / 250 = 0.396

3 0
2 years ago
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