You left it out, but I'm thinking that there must be an 'x' next to the '20.50' in the function. I'm so sure of it that I'll assume it, as I proceed to answer the question:
C(x) = 20.50x + 2,000
Subtract 2,000 from each side: C - 2,000 = 20.50 x
Divide each side by 20.50 : x = (C - 2,000) / 20.50
When C = $625,000 . . .
x = (625,000 - 2,000) / 20.50 = 623,000 / 20.50 = 30,390.2439
<em>30,390 complete units</em> are produced, and there are 5 bucks left over,
to split up among all the loyal employees who worked with such diligence and dedication to make it happen. The company's senior management will graciously add each worker's share to his gross pay before taxes for the second month following the close of the current quarter, with a photocopied note inserted in the pay envelope, expressing management's sincere thanks to everyone, an admonition not to spend it all in one place, and a reminder that no matter how many festivals to their god they need to go out to the desert to celebrate, their tally of bricks for the next quarter shall not be diminished.
The given expression is

And in the second factor, x is common. So on taking x out, we will get

We can expand it by distributing , that is


Combining like terms,

And that's the expanded form ., and the given expression can also be written in that way .
Answer:
x = 74°
Step-by-step explanation:
Same side interior angles are supplementary meaning they must add up to 180°.
x = 180° - 106°
x = 74°
Answer:
Question 9 = 5.5 hours (Cross multiplication)
Answer:

Step-by-step explanation:
<u>Electric Field</u>
The electric field produced by a point charge Q at a distance d is given by

Where

The net electric field is the vector addition of the individual electric fields produced by each charge. The direction is given by the rule: If the charge is positive, the electric field points outward, if negative, it points inward.
Let's calculate the electric fields of each charge at the given point. The first charge
is at the origin. We'll calculate its electric field at the point x=-3.85 cm. The distance between the charge and the point is d=3.85 cm = 0.0385 m, and the electric field points to the left:


Similarly, for
, the distance to the point is 12 cm + 3.85 cm = 15.85 cm = 0.1585 m. The electric field points to the right:


Since E1 and E2 are opposite, the net field is the subtraction of both

