Question

Find the x-component of this vector: 15.3 m 65.0° Please help!

Answer 1

Given :

Magnitude of vector, v = 15.3 m

Angle of vector from horizon, $\theta = 65^o$ .

To Find :

The x - component of the given vector.

Solution :

We know, a vector is given by :

$\vec{v} = vsin\ \theta \hat{i} + v cos \ \theta \hat{j}$

Now, the x - component is :

$\vec{v_x} = vcos\ \theta \hat{j}\\\\\vec{v_x} = 15.3 \times cos\ 65^o \hat{j}\\\\\vec{v_x} = 15.3 \times 0.42\ \hat{j}\\\\\vec{v_x} = 6.426\ \hat{j}$

Hence, this is the required solution.